use*_*214 -2 c++ switch-statement
我的问题是,当switch语句指示时,此函数将guess返回为97和y的总和,而不仅仅是字母.奇怪的是,当我拥有它只是返回y时,它正如我所期望的那样工作.例如,当y = 4,并且我返回y时,显示4.当y = 4并且返回'guess'时,显示101.免责声明:这不是完整的代码.它真的很长,我觉得多余,因为我唯一的问题是当这个特定的函数返回'guess'时,即使它返回y也没有.如果所有代码都有用,我会很乐意提出来.
int letterguess(int z){
char guess;
int y;
y=letters[0][z];
switch (y){
case 0:
guess='a';
break;
case 1:
guess='b';
break;
case 2:
guess='c';
break;
case 3:
guess='d';
break;
case 4:
guess='e';
break;
case 5:
guess='f';
break;
case 6:
guess='g';
break;
case 7:
guess='h';
break;
case 8:
guess='i';
break;
case 9:
guess='j';
break;
case 10:
guess='k';
break;
case 11:
guess='l';
break;
case 12:
guess='m';
break;
case 13:
guess='n';
break;
case 14:
guess='o';
break;
case 15:
guess='p';
break;
case 16:
guess='q';
break;
case 17:
guess='r';
break;
case 18:
guess='s';
break;
case 19:
guess='t';
break;
case 20:
guess='u';
break;
case 21:
guess='v';
break;
case 22:
guess='w';
break;
case 23:
guess='y';
break;
case 24:
guess='y';
break;
case 25:
guess='z';
break;
}
return guess;
}
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我真的看不出这可能会像这样搞砸了.提前致谢.
Oli*_*rth 11
这正是你告诉它要做的.在标准ASCII字符集中,a具有值97等.
这不是完全清楚你在做什么尝试做的,虽然.您已将函数的返回类型指定为int,但是您将返回值设置为字符文字.如果你想返回一个你可以显示的字符,我建议你将返回类型更改为char,并执行以下操作:
char c = letterguess(blah);
std::cout << c << "\n";
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