Tho*_*asK 32 php oop pagination class paginate
谷歌的分页行为背后的逻辑是什么？
我的分页器是这样的:
[1] 2 3 ... 184 >
< 1 [2] 3 4 ... 184 >
< 1 2 [3] 4 5 ... 184 >
< 1 2 3 [4] 5 6 ... 184 >
< 1 ... 3 4 [5] 6 7 ... 184 >
< 1 ... 4 5 [6] 7 8 ... 184 >
< 1 ... 5 6 [7] 8 9 ... 184 >
< 1 ... 6 7 [8] 9 10 ... 184 >
以下是上述示例的实时版本:http://www.dev.thomaskile.me/？page = test-zone&modules = Pepinator.
我知道为什么会这样; 我已将当前页面每一侧显示的页码数量设置为两(2).
我宁愿让数字范围像这样:
[1] 2 3 4 5 6 7 8 ... 184 >
< 1 [2] 3 4 5 6 7 ... 184 >
< 1 2 [3] 4 5 6 7 ... 184 >
< 1 2 3 [4] 5 6 7 ... 184 >
< 1 ... 3 4 [5] 6 7 ... 184 >
< 1 ... 4 5 [6] 7 8 ... 184 >
< 1 ... 5 6 [7] 8 9 ... 184 >
< 1 ... 6 7 [8] 9 10 ... 184 >
它是在开始和结束时我需要做出一些改变,但无法弄清楚如何使它变得简单操作......
我也想让它变得灵活.意思是我希望能够改变每一侧所需页面的数量,并让脚本扩展并计算所有...
到目前为止,这是我的代码:
/**
* page controller buttons
* @param str $this->querySting href="URL string"
* @param str $this->pageIdentifier $_GET['this-name']
* @param int $this->numPages Total amount of pages
* @param int $this->midRange Number of pages to show on each side of current page
*/
public function prevPage()
{
if ($this->currentPage > 1){
$prevPage = ($this->currentPage - 1);
return '<a href="'.$this->queryString.'&'.$this->pageIdentifier.'='.$prevPage.'" class="prev">prev</a>';
}
}
public function nextPage()
{
if ($this->currentPage < $this->numPages) {
$nextPage = $this->currentPage + 1;
return '<a href="'.$this->queryString.'&'.$this->pageIdentifier.'='.$nextPage.'" class="next">next</a>';
}
}
public function firstPage()
{
if ($this->currentPage > ($this->midRange + 1)) { // if number of pages between "currentPage" and "firstPage" exceeds $midRange with 1...
$firstPage .= '<a href="'.$this->queryString.'&'.$this->pageIdentifier.'=1" class="first">1</a>'; // ...show "first page"-link
if ($this->currentPage > ($this->midRange + 2)) { // if number of pages between $currentPage and "first page" exceeds $midRange with more than 1
$firstPage .= '…'; // add "..." between "1st page"-link and first page in $range
}
}
return $firstPage;
}
public function lastPage()
{
if ($this->currentPage < ($this->numPages - $this->midRange)) { // if number of pages between "currentPage" and "last page" is equal to $midRange
if (($this->currentPage < ($this->numPages - $this->midRange) - 1)) { // if number of pages between $currentPage and "last page" exceeds $range with more than two
$lastPage .= '…'; // add "..." between "last page"-link and last page in $range
}
$lastPage .= '<a href="'.$this->queryString.'&'.$this->pageIdentifier.'='.$this->numPages.'" class="last">'.$this->numPages.'</a>'; // show "last page"-link
}
return $lastPage;
}
# Range of pages between (prev first ...) and (... last next)
public function listPages()
{
for ($i = ($this->currentPage - $this->midRange); $i < (($this->currentPage + $this->midRange) + 1); $i++){
if (($i > 0) && ($i <= $this->numPages)) // if page number are within page range
{
if ($i == $this->currentPage) { $listPages .= '<a class="current">'.$i.'</a>'; } // if we're on current page
else { $listPages .= '<a href="'.$this->queryString.'&'.$this->pageIdentifier.'='.$i.'">'.$i.'</a>'; } // if not current page
}
}
return $listPages;
}
inv*_*sal 40
这就是我为我的分页做的事情.
$startPage = $currentPage - 4;
$endPage = $currentPage + 4;
if ($startPage <= 0) {
$endPage -= ($startPage - 1);
$startPage = 1;
}
if ($endPage > $totalPage)
$endPage = $totalPage;
if ($startPage > 1) echo " First ... ";
for($i=$startPage; $i<=$endPage; $i++) echo " {$i} ";
if ($endPage < $totalPage) echo " ... Last ";
我相信我的代码是自我解释的,但我会尝试用简单的英语解释它.首先,在生成分页之前,您需要先了解两件事:$ totalPage和$ currentPage.
第1步:假设当前页面处于中间范围.$ startPage和$ endPage存储分页尝试生成的页面范围.
第2步:如果$ startPage为负数,那么你需要化妆$ endPage.
第3步:如果$ endPage超过$ totalPage,则$ endPage是最后一页.
第4步:将分页生成为HTML.(这取决于你希望你的分页看起来如何.我将简单地使用纯文本来表示我的分页)
if ($startPage > 1) echo " First ... ";
for($i=$startPage; $i<=$endPage; $i++) echo " {$i} ";
if ($endPage < $totalPage) echo " ... Last ";
修复了我之前逻辑的缺陷
$startPage = ($curPage < 5)? 1 : $curPage - 4;
$endPage = 8 + $startPage;
$endPage = ($totalPage < $endPage) ? $totalPage : $endPage;
$diff = $startPage - $endPage + 8;
$startPage -= ($startPage - $diff > 0) ? $diff : 0;
if ($startPage > 1) echo " First ... ";
for($i=$startPage; $i<=$endPage; $i++) echo " {$i} ";
if ($endPage < $totalPage) echo " ... Last ";
这次谈话对我来说是一个很好的开始!但我希望分页符更接近原始问题的意图,即:
1)可以包含在具有变量的函数中,以改变当前要显示的当前页面和当前页面的页面数量.
2)保持恒定的宽度,类似于原始帖子:
< [1] 2 3 4 5 6 7 ... 99 >
< 1 [2] 3 4 5 6 7 ... 99 >
< 1 2 [3] 4 5 6 7 ... 99 >
< 1 2 3 [4] 5 6 7 ... 99 >
< 1 2 3 4 [5] 6 7 ... 99 >
< 1 ... 4 5 [6] 7 8 ... 99 >
< 1 ... 5 6 [7] 8 9 ... 99 >
< 1 ... 92 93 [94] 95 96 ... 99 >
< 1 ... 93 94 [95] 96 97 98 99 >
< 1 ... 93 94 95 [96] 97 98 99 >
< 1 ... 93 94 95 96 [97] 98 99 >
< 1 ... 93 94 95 96 97 [98] 99 >
< 1 ... 93 94 95 96 97 98 [99] >
3)在你有1 ... 3的情况下继续显示数字"2"而不是"..."
4)结束时同样的事情.
所以这就是我做的.我使用不同的语言(coffeescript)进行编码,但无论如何它应该起到良好的sudo-code的作用:
get_pages_array = (total_page, each_side, curr_page) ->
if total_page <= (2*each_side)+5
# in this case, too few pages, so display them all
start_page = 1
end_page = total_page
else if curr_page<=each_side+3
# in this case, curr_page is too close to the beginning
start_page = 1
end_page = (2*each_side)+3
else if curr_page >= total_page - (each_side+2)
# in this case, curr_page is too close to the end
start_page = total_page - (2*each_side) - 2
end_page = total_page
else
# regular case
start_page = curr_page - each_side
end_page = curr_page + each_side
return_me = []
if start_page> 1
return_me.push "1"
if start_page>2
return_me.push "..."
for x in [start_page..end_page]
return_me.push x
if end_page<total_page-1
return_me.push "..."
if end_page<total_page
return_me.push total_page
return return_me
我在each_side = 2上使用这个代码,所以我确定它的工作原理.
编辑:根据@Vextil修复逻辑