ezz*_*rem 4 c synchronization mpi master-slave
我有一个使用MPI同步主/从进程的问题.我希望主控制从属执行的顺序.Eeach奴隶必须做:1-读2过程.这是我的代码:
int main(int argc, char* argv []){
int rank,numprocess;
MPI_Init( &argc, &argv );
MPI_Comm_rank( MPI_COMM_WORLD, &rank );
MPI_Comm_size( MPI_COMM_WORLD, &numprocess );
if(rank==0){ //master
MPI_Status s;int Sstate=1;int Rstate;
int p;
for(p=1;p<numprocess;p++){
fflush(stdout);printf("master : order P%d to start reading\n",p);
MPI_Send(&Sstate, sizeof(int), MPI_INT, p, 20, MPI_COMM_WORLD);
MPI_Recv(&Rstate,sizeof(int),MPI_INT,p,21,MPI_COMM_WORLD,&s);
fflush(stdout);printf("master : P%d finished reading\n",p);
}
}
else{ //workers
int state; MPI_Status s;
MPI_Recv(&state,sizeof(int),MPI_INT,0,20,MPI_COMM_WORLD,&s);
//read here
Sleep(1000);
//send to master : finish reading
state=2;
MPI_Send(&state, sizeof(int), MPI_INT, 0, 21, MPI_COMM_WORLD);
//processing
Sleep(3000);
fflush(stdout);printf("worker %d ended processing\n",rank);
}
MPI_Finalize();
return 0;
}
Run Code Online (Sandbox Code Playgroud)
我的问题是最后一个过程.事实上它并没有像其他人那样行事.这是我的输出:
mpiexec -n 4 master.exe
master : order P1 to start reading
master : p1 finished reading
master : order P2 to start reading
master : p2 finished reading
master : order P3 to start reading
worker 1 ended processing
worker 2 ended processing
master : p3 finished reading
worker 3 ended processing
Run Code Online (Sandbox Code Playgroud)
为什么第三个进程不同步?谢谢你的宝贵帮助!
对于多线程或多进程架构,您所展示的是Normal.基本上,在您的进程调用MPI_Send主进程之后,它们将被释放以自行运行,因为它们没有更多的阻塞MPI调用.因此,他们睡觉后,他们打印他们的结束声明,彼此独立和主人本身!
下面我有一个图表,我希望能够说明你所看到的:
