我可以在 Meta Http Equiv Refresh 中传递变量吗？

Question

我刚刚完成这个脚本，它运行良好，但我很难将 $invite 变量传递到 register.php 页面。有人可以告诉我如何实现这一目标吗？我将其定义为 $invite = $_POST['inviteinput'];

如何将用户输入从index.php传输到register.php？感谢您的帮助！

HTML 格式：

    <form action="index.php" method="post">
    What is your Invite Code?<BR />
    <input class="textbox" name="inviteinput" type="text" />
    <BR />
    <input type="hidden" name="formsubmitted" value="TRUE" />
    <input name="Submit" type="submit" value="Verify" />
    </form>

PHP：

<?PHP
include ('scripts/dbconnect.php');

if (isset($_POST['formsubmitted'])) {

if (empty($_POST['inviteinput'])) {
echo '<div class="errormsgempty"><u>ERROR</u>:<br>You must enter a valid invite code to proceed!</div>';
} else {


$invite = $_POST['inviteinput'];//else assign it a variable
$invite = stripslashes($invite);
$invite = mysql_real_escape_string($invite);

$sql = "SELECT yourMemberId FROM Register WHERE yourMemberId='$invite'";
$result = mysql_query($sql);

if(mysql_num_rows($result) > 0) {

echo '<META HTTP-EQUIV="Refresh" Content="0; URL=register.php">';   
} else { 
echo '<div class="errormsgbox"><u>ERROR</u>:<br>The Invite Code you entered ' . $invite . ' is NOT a valid invite code!</div>';
//($notvalidcode = "The Invite Code you entered <strong>" . $invite . "</strong> is NOT a valid invite code!");
}
}
}
?>

Answer 1

绝对地。只需将其添加到 URL 即可：

<meta http-equiv="Refresh" Content="0; url=register.php?var=value&othervar=hello" />

请注意，您最好使用：

header("Location: register.php?var=value&othervar=hello");
exit;