我在这张表中有以下数据
Job Quantity Status Repeat
1 100 OK 2
2 400 HOLD 0
3 200 HOLD 1
4 450 OK 3
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根据每行的"重复"列中的值,应再次重复该行.例如,对于作业1,重复值为2,因此作业1应重复两次.
结果表应如下所示
Job Quantity Status Repeat
1 100 OK 2
1 100 OK 2
1 100 OK 2
2 400 HOLD 0
3 200 HOLD 1
3 200 HOLD 1
4 450 OK 3
4 450 OK 3
4 450 OK 3
4 450 OK 3
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有人可以帮我解决这个问题吗?我正在使用oracle 10g
您可以使用递归CTE:
with cte(Job, Repeat, i) as
(
select Job
, Repeat
, 0
from YourTable
union all
select Job
, Repeat
, i + 1
from cte
where cte.i < cte.Repeat
)
select *
from cte
order by
Job
, i
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假设每行不会生成超过1000行:
with num as (select level as rnk from dual connect by level<=1000)
select Job, Quantity, Status, Repeat, rnk
from t join num on ( num.rnk <= repeat )
order by job, rnk;
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这是一个测试:http: //sqlfiddle.com/#!4/4519f/12
更新:正如Jeffrey Kemp所说,你可以用子查询"检测"最大值:
with num as (select level as rnk
from dual
connect by level<=(select max(repeat) from t)
)
select job, quantity, status, repeat, rnk
from t join num on ( num.rnk <= repeat )
order by job, rnk;
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