根据每行中的列值重复行

use*_*255 7 sql oracle

我在这张表中有以下数据



Job  Quantity   Status  Repeat 
1    100         OK     2 
2    400         HOLD   0 
3    200         HOLD   1 
4    450         OK     3 
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根据每行的"重复"列中的值,应再次重复该行.例如,对于作业1,重复值为2,因此作业1应重复两次.

结果表应如下所示



Job      Quantity   Status  Repeat 
1        100        OK      2 
1        100        OK      2 
1        100        OK      2 
2        400        HOLD    0 
3        200        HOLD    1 
3        200        HOLD    1 
4        450        OK      3 
4        450        OK      3 
4        450        OK      3 
4        450        OK      3 

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有人可以帮我解决这个问题吗?我正在使用oracle 10g

And*_*mar 8

您可以使用递归CTE:

with    cte(Job, Repeat, i) as 
        (
        select  Job
        ,       Repeat
        ,       0
        from    YourTable
        union all
        select  Job
        ,       Repeat
        ,       i + 1
        from    cte
        where   cte.i < cte.Repeat
        )
select  *
from    cte
order by
        Job
,       i
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SQL Fiddle的实例.


Flo*_*ita 7

假设每行不会生成超过1000行:

with num as (select level as rnk from dual connect by level<=1000)
select Job,  Quantity,   Status,  Repeat, rnk 
from t join num on ( num.rnk <= repeat )
order by job, rnk;
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这是一个测试:http: //sqlfiddle.com/#!4/4519f/12

更新:正如Jeffrey Kemp所说,你可以用子查询"检测"最大值:

with num as (select level as rnk 
             from dual 
             connect by level<=(select max(repeat) from t)
             )
select job,  quantity,   status,  repeat, rnk 
from t join num on ( num.rnk <= repeat )
order by job, rnk;
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