你如何从地址簿中获得一个人的电话号码？

Question

我想要做的就是让用户从地址簿中选择一个号码.我在这个问题中找到了代码:

如何从地址簿联系人处获取电话号码(iphone sdk)

ABMultiValueRef container = ABRecordCopyValue(person, property);
CFStringRef contactData = ABMultiValueCopyValueAtIndex(container, identifier);
CFRelease(container);
NSString *contactString = [NSString stringWithString:(NSString *)contactData];
CFRelease(contactData);

问题是在第二行(在3.0设备上运行时)我收到以下错误:

客户经理无法找到标识为MobileMe:rustyshelf的帐户

其次是:

程序接收信号:"EXC_BAD_ACCESS".

这都在picker委托方法中:

- (BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier{

这只是我的地址簿中的一个联系人,它与Mobile Me同步

编辑:我认为这可能是SDK的一个错误,它发生在我的一些联系人,而不是其他人...

Answer 1

"identifier"参数不包含所触摸记录的CFIndex.我用来判断用户选择的电话号码的方法是:

- (BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier
{
    if (property == kABPersonPhoneProperty) {
        ABMultiValueRef multiPhones = ABRecordCopyValue(person, kABPersonPhoneProperty);
        for(CFIndex i = 0; i < ABMultiValueGetCount(multiPhones); i++) {
            if(identifier == ABMultiValueGetIdentifierAtIndex (multiPhones, i)) {
                CFStringRef phoneNumberRef = ABMultiValueCopyValueAtIndex(multiPhones, i);
                CFRelease(multiPhones);
                NSString *phoneNumber = (NSString *) phoneNumberRef;
                CFRelease(phoneNumberRef);
                txtPhoneNumber.text = [NSString stringWithFormat:@"%@", phoneNumber];
                [phoneNumber release];
            }
        }
    }

    [self dismissModalViewControllerAnimated:YES];
    return NO;
}

Answer 2

关于JWD的回答,这是一个更安全的版本,它使用内置常量并选择iphone号码而不是另一个手机号码......

ABMultiValueRef phones =(NSString*)ABRecordCopyValue(person, kABPersonPhoneProperty);
NSString* mobile=@"";
NSString* mobileLabel;
for(CFIndex i = 0; i < ABMultiValueGetCount(phones); i++) {
    mobileLabel = (NSString*)ABMultiValueCopyLabelAtIndex(phones, i);
    if([mobileLabel isEqualToString:(NSString *)kABPersonPhoneMobileLabel])
    {
        [mobile release] ;
        mobile = (NSString*)ABMultiValueCopyValueAtIndex(phones, i);
    }
    else if ([mobileLabel isEqualToString:(NSString*)kABPersonPhoneIPhoneLabel])
    {
        [mobile release] ;
        mobile = (NSString*)ABMultiValueCopyValueAtIndex(phones, i);
        break ;
    }
}

Answer 3

- (BOOL)personViewController:(ABPersonViewController *)personViewController shouldPerformDefaultActionForPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifierForValue
{
   if (property == kABPersonPhoneProperty)
   {
       ABMultiValueRef numbers = ABRecordCopyValue(person, property);
       NSString* targetNumber = (__bridge NSString *) ABMultiValueCopyValueAtIndex(numbers, ABMultiValueGetIndexForIdentifier(numbers, identifierForValue));

       NSLog(@"%@", targetNumber);
   }
   return NO;
}

我用这个问题来构建我自己的解决方案.我发布的代码不是作为答案,仅仅是为了找到有用的人.这些是获取房产的简单步骤.内存管理除外.

Answer 4

您应该能够执行以下操作：

ABMultiValueRef phoneNumbers = (ABMultiValueRef)ABRecordCopyValue(person, kABPersonPhoneProperty);
CFRelease(phoneNumbers);
NSString* phoneNumber = (NSString*)ABMultiValueCopyValueAtIndex(phoneNumbers, 0);

当然，这只会让您获得与被选中的人相关的（可能）许多个中的第一个数字。