列与unpivot列表中的其他列的类型冲突

Dar*_*ver 29 sql t-sql sql-server-2008

sys.[views]转入键值对,与另一台服务器上的值进行比较,以进行一致性测试.我遇到了一个返回错误的问题.

消息8167,第16级,状态1,第51行

列"type"的类型与UNPIVOT列表中指定的其他列的类型冲突.

查询:

SELECT
sourceUnpivoted.idServer,
sourceUnpivoted.sourceServerName,
sourceUnpivoted.name,
sourceUnpivoted.columnName,
sourceUnpivoted.columnValue
FROM (
SELECT 
CAST('1' AS VARCHAR(255)) AS idServer,
CAST('thisOne' AS VARCHAR(255)) AS sourceServerName,
CAST('theDatabase' AS VARCHAR(255)) AS sourceDatabaseName,
CAST(name AS VARCHAR(255)) AS name,
CAST(object_id AS VARCHAR(255)) AS object_id,
CAST(principal_id AS VARCHAR(255)) AS principal_id,
CAST(schema_id AS VARCHAR(255)) AS schema_id,
CAST(parent_object_id AS VARCHAR(255)) AS parent_object_id,
CAST(type AS VARCHAR(255)) AS type,
CAST(type_desc AS VARCHAR(255)) AS type_desc,
CAST(create_date AS VARCHAR(255)) AS create_date,
CAST(lock_escalation_desc AS VARCHAR(255)) AS lock_escalation_desc
...
FROM noc_test.dbo.stage_sysTables
) AS databaseTables
UNPIVOT (
columnValue FOR columnName IN (
object_id,
principal_id,
schema_id,
parent_object_id,
type,
type_desc,
create_date,
lock_escalation_desc
) 
) AS sourceUnpivoted
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为什么这个不喜欢[type],[type_desc],[lock_escalation_desc]??? 我也试过了CONVERT(VARCHAR(255),type) AS type

Dam*_*ver 32

这实际上是一个整理问题.我可以通过更改这些行来解决它:

CAST([type] collate database_default AS VARCHAR(255)) AS [type], 
CAST(type_desc collate database_default AS VARCHAR(255)) AS type_desc, 
CAST(create_date AS VARCHAR(255)) AS create_date, 
CAST(lock_escalation_desc collate database_default AS VARCHAR(255)) AS lock_escalation_desc 
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具体问题是name整理为Latin1_General_CI_AS,而你提到的其他3列整理为Latin1_General_CI_AS_KS_WS(至少,在我的机器上,我不知道在具有不同默认排序规则的服务器/数据库上会是什么样).


小智 19

这是此类型错误的解决方案之一

1:创建此表

CREATE TABLE People
(
PersonId int, 
Firstname varchar(50), 
Lastname varchar(25)
)
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2:然后插入

INSERT INTO People VALUES (1, 'Jim', 'Smith');
INSERT INTO People VALUES (2, 'Jane', 'Jones');
INSERT INTO People VALUES (3, 'Bob', 'Unicorn');
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3:运行此脚本会出现错误

消息8167,级别16,状态1,行3"Lastname"列的类型与UNPIVOT列表中指定的其他列的类型冲突.

SELECT PersonId, ColumnName, Value
FROM People
unpivot(Value FOR ColumnName IN (FirstName, LastName)) unpiv;
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4:解决方案是您必须使用子查询首先将Lastname列转换为与Firstname具有相同的长度

SELECT PersonId, ColumnName, Value
FROM (
SELECT personid, firstname, cast(lastname AS VARCHAR(50)) lastname
FROM People
) d
unpivot(Value FOR ColumnName IN (FirstName, LastName)) unpiv;
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小智 5

PIVOT/UNPIVOT 子句对列的 ANSI 填充状态(SSMS 中的右键单击 -> 属性)以及类型、大小和排序规则敏感。在添加或重新创建相关列之前,尝试在会话中指定 SET ANSI_PADDING ON|OFF,以便它与 PIVOT/UNPIVOT 子句中的其他列匹配。


Sli*_*SFT 5

遇到了同样的错误,我只是让表中的所有列都具有相同的数据类型 - 我混合了int, varchar,nvarchar各种长度。一旦我将表中的所有列都转换为相同的类型 -nvarchar(255)它工作得很好。