我有2个文本字段,用于登录ID和密码.当用户点击电子邮件ID时,他们的键盘类型是电子邮件,密码是其默认值.他们完成了两个键盘按钮,解开了键盘.我想要做的是,一旦用户填写了id和密码,他们的DONE按钮应该更改为"LOGIN",我可以在它上面执行选择器方法登录.
这可行吗?
谢谢
如果您使用的是标准iOS键盘,那么唯一可用的返回键类型是
typedef enum {
UIReturnKeyDefault, // “Return”
UIReturnKeyGo, // “Go”
UIReturnKeyGoogle, // “Google”.
UIReturnKeyJoin, // “Join”.
UIReturnKeyNext, // “Next”.
UIReturnKeyRoute, // “Route”.
UIReturnKeySearch, // “Search”.
UIReturnKeySend, // “Send”.
UIReturnKeyYahoo, // “Yahoo”.
UIReturnKeyDone, // “Done”
UIReturnKeyEmergencyCall, // "Emergency Call”.
} UIReturnKeyType;
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要检测键盘上的键更改,您可以注册名称:UITextFieldTextDidChangeNotification.让我们说你的textfield是emailTextField和passwordTextField.
首先注册通知,检测文本输入
// emailTextField
[[NSNotificationCenter defaultCenter] addObserver:self
selector:@selector(check)
name:UITextFieldTextDidChangeNotification
object:emailTextField];
// passwordTextField
[[NSNotificationCenter defaultCenter] addObserver:self
selector:@selector(check)
name:UITextFieldTextDidChangeNotification
object:passwordTextField];
- (void)check {
if ([emailTextField.text length] > 0 && [passwordTextField.text length] > 0) {
// Set the return key here, e.g:
emailTextField.returnKeyType = UIReturnKeyGo;
passwordTextField.returnKeyType = UIReturnKeyGo;
}
else {
// Set the return key here, e.g:
emailTextField.returnKeyType = UIReturnKeyNext;
passwordTextField.returnKeyType = UIReturnKeyNext;
}
}
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当点击返回键时,它将调用textfield delegate.你可以这样做:
- (BOOL)textFieldShouldReturn:(UITextField *)textField
{
// You can perform selector here, probably after checking if both of the textfields already filled out. E.g:
if ([emailTextField.text length] > 0 && [passwordTextField.text length] > 0) {
[self performSelector:@selector(login)];
}
return YES;
}
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