在MySQL表中查找"异国情调"值

Old*_*ool 5 mysql sql count

我有一个名为MySQL的表accounts.在此表中是一个名为的字段salesmanager_id.99%的情况下,此字段中的值对于特定客户(指定的customer_id)的所有帐户始终相同.

我要做的是找到customer_id分配给多个销售经理的客户.例如:

+------------------------------------+
| id | customer_id | salesmanager_id |
|------------------------------------|
| 1  | 12          | 4               |
| 2  | 12          | 4               |
| 3  | 14          | 3               | <-- I want this customer_id
| 4  | 14          | 4               |
+------------------------------------+
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在上面的例子中,customer_id14 salesmanager_id分配了3和4.我想找回customer_id我的清单.

我尝试了以下查询,但返回一个空结果(虽然我确定至少存在一些差异).

SELECT `name`, `customer_id` AS `customer`, `salesmanager_id` FROM `accounts`
WHERE `salesmanager_id` NOT IN (
    SELECT `salesmanager_id` FROM `accounts` a
    LEFT JOIN `customers` c ON (a.customer_id = c.id)
    WHERE a.customer_id=c.id
) GROUP BY `customer`;
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Zan*_*ien 13

SELECT 
    customer_id
FROM 
    accounts
GROUP BY 
    customer_id
HAVING 
    COUNT(DISTINCT salesmanager_id) > 1
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这基本上得到salesmanager_id了每个的所有s,customer_id如果有多个唯一salesmanager_id值,customer_id则返回.