NSPredicate'OR'过滤基于NSArray键

Question

考虑以下NSArray:

NSArray *dataSet = [[NSArray alloc] initWithObjects:
                 [NSDictionary dictionaryWithObjectsAndKeys:@"abc", @"key1", @"def", @"key2", @"hij", @"key3", nil], 
                 [NSDictionary dictionaryWithObjectsAndKeys:@"klm", @"key1", @"nop", @"key2", nil], 
                 [NSDictionary dictionaryWithObjectsAndKeys:@"qrs", @"key2", @"tuv", @"key4", nil], 
                 [NSDictionary dictionaryWithObjectsAndKeys:@"wxy", @"key3", nil], 
                 nil];

我能够过滤此数组以查找包含密钥的字典对象 key1

// Filter our dataSet to only contain dictionary objects with a key of 'key1'
NSString *key = @"key1";
NSPredicate *key1Predicate = [NSPredicate predicateWithFormat:@"%@ IN self.@allKeys", key];
NSArray *filteretSet1 = [dataSet filteredArrayUsingPredicate:key1Predicate];
NSLog(@"filteretSet1: %@",filteretSet1);

适当回报:

filteretSet1: (
        {
        key1 = abc;
        key2 = def;
        key3 = hij;
    },
        {
        key1 = klm;
        key2 = nop;
    }
)

现在,我想过滤包含NSArray 中任何键的字典对象的dataSet .

例如,使用数组:NSArray *keySet = [NSArray arrayWithObjects:@"key1", @"key3", nil];我想创建一个谓词,返回包含'key1' 或 'key3' 的任何字典对象的数组(即在此示例中,除第三个对象外,将返回所有字典对象 - 如它不包含'key1' 或 'key3').

有关如何实现这一目标的任何想法？我是否必须使用复合谓词？

Answer 1

该ANY运营商NSPredicate覆盖这样的:

NSSet *keys = [NSSet setWithObjects:@"key1", @"key3", nil];

NSPredicate *key1Predicate = [NSPredicate predicateWithFormat:@"any self.@allKeys in %@", keys];