Mic*_*l-O 3 sql oracle pivot pivot-table
我想在Oracle 11g中旋转一个表.pivot选项需要聚合.这是我原来的表:
project | attribute | value
===========================
'cust1' | 'foo' | '4'
'cust2' | 'bar' | 'tbd'
'cust3 | 'baz' | '2012-06-07'
'cust1' | 'bar' | 'tdsa'
'cust4' | 'foo' | '22'
'cust4' | 'baz' | '2013-01-01'
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在旋转之后,表格应如下所示:
project | foo | bar | baz
=========================
'cust1' | '4' |'tdba'| NULL
'cust2' | NULL|'tbd' | NULL
'cust3' | NULL| NULL | '2012-06-07'
'cust4' | '22'| NULL | '2013-01-01'
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现在,正如您所看到的,分组应该在项目列上进行.没有值需要折叠或计算.仅仅轮换是必要的.那么,枢轴选择正确的做法是什么?
是的,我想是这样.使用MAX聚合很容易做这样的枢轴:
SELECT
*
FROM
(
SELECT
project,
attribute,
value
FROM
table1
) AS SourceTable
PIVOT
(
MAX(value)
FOR attribute IN ([foo],[bar],[baz])
) AS pvt
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否则你必须在最大聚合内部做一个case语句.像这样:
SELECT
MAX(CASE WHEN attribute='foo' THEN value ELSE NULL END) AS foo,
MAX(CASE WHEN attribute='bar' THEN value ELSE NULL END) AS bar,
MAX(CASE WHEN attribute='baz' THEN value ELSE NULL END) AS baz,
project
FROM
table1
GROUP BY
project
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这几乎和做的一样PIVOT.但我宁愿做PIVOT在CASE WHEN MAX..