是否有正确的方法来$.扩展jQuery中的嵌套属性？

Question

我拥有什么,我需要什么.这很简单.

默认选项(有嵌套属性):

{
  sDom: 'frt<"tfoot"lp>',
  bInfo: false,
  sPaginationType: "full_numbers",
  oLanguage: {
    sSearch: "",
    sLengthMenu: "Show _MENU_",
    oPaginate: {
      sFirst:     "|<<",
      sLast:      ">>|",
      sNext:      ">>",
      sPrevious:  "<<"
    }
  }
}

实际选项:

{
  oLanguage: {
    oPaginate: {
      sNext:      "MODIFIED"
    }
  }
}

$ .extend的结果:

{
  sDom: 'frt<"tfoot"lp>',
  bInfo: false,
  sPaginationType: "full_numbers",
  oLanguage: {
    oPaginate: {
      sNext:      "MODIFIED"
    }
  }
}

我需要的是使用实际选项正确扩展默认选项并获得以下结果(一个属性已被修改):

{
  sDom: 'frt<"tfoot"lp>',
  bInfo: false,
  sPaginationType: "full_numbers",
  oLanguage: {
    sSearch: "",
    sLengthMenu: "Show _MENU_",
    oPaginate: {
      sFirst:     "|<<",
      sLast:      ">>|",
      sNext:      "MODIFIED"
      sPrevious:  "<<"
    }
  }
}

问题是$ .extend函数忽略嵌套属性并仅操作第一级属性.现在我手动$ .extend每个嵌套属性,但我想这不是一个解决方案.

Answer 1

通过传递第一个参数,您需要一个递归副本true:

var defaults = {...}
var actual = {...}

//recursively merge to a blank object
console.log($.extend(true,{}, defaults, actual))?