如何检测XML元素是否具有子元素

mkt*_*012 2 perl libxml2

我正在使用CPAN XML::LibXML模块处理下面的XML数据.我需要确定每个元素是否都有子元素.搜索我无法找到任何这样的例子.

<A>
    <ts>2012</ts>
    <T>M1</T>
    <T>M2</T>
    <B>
        <id>PC</id>
        <r>10</r>
        <r>30</r>
    </B>
</A>
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这是我写的Perl代码

#!/usr/bin/perl

use strict;
use warnings;

use XML::LibXML;

my ($x,$elname,$haschild)= ();
my $parser = XML::LibXML->new();
my $npo    = $parser->parse_file("test.xml");
my $rootel = $npo -> getDocumentElement();
$elname = $rootel -> nodeName();
print "Root name=$elname\n";

foreach $x ($rootel->childNodes) {
    $elname = $x -> nodeName();
    $haschild = $x->hasChildNodes;
    print "Child name = $elname and has child = $haschild.\n" unless ($elname =~ /#text/i);
}
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虽然我过去childNodes经历过每个节点,但我找不到一种简单的方法来确定节点是否有孩子.

我希望在遍历所有节点之后得到结果:

A: Has children
ts: Has none
T: has none
T: has none
B: Has children
id: Has none
r: Has none
r: Has none
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我得到的结果是这样的:

Root name=A
Child name = ts and has child = 1.
Child name = T and has child = 1.
Child name = T and has child = 1.
Child name = B and has child = 1.
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hasChildNodes条件检查后,似乎所有节点都返回true .

Bor*_*din 5

您要求的是节点的子元素数.子节点将包括文本和无关紧要的空白.

计算节点具有的子元素数量的最简单方法是使用findnodes('*')->sizeXPath表达式*仅计算子元素.

这是一些代码,可以完成您所描述的内容

use v5.14;
use warnings;

use XML::LibXML;

my $xml = XML::LibXML->load_xml(string => <<XML);
<A>
    <ts>2012</ts>
    <T>M1</T>
    <T>M2</T>
    <B>
        <id>PC</id>
        <r>10</r>
        <r>30</r>
    </B>
</A>
XML

my $nodes = $xml->findnodes('//*');
foreach my $node ($nodes->get_nodelist) {
  my $children;
  for ($node->findnodes('*')->size) {
    $children = 'none' when 0;
    $children = '1 child' when 1;
    default { $children = "$_ children" }
  }
  printf "%s: has %s\n", $node->localname, $children;
}
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产量

A: has 4 children
ts: has none
T: has none
T: has none
B: has 3 children
id: has none
r: has none
r: has none
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