如何使用org.apache.commons.codec.binary.base64对Java对象进行Base64编码？

Question

我一直在尝试对象序列化和Base64编码结果.它适用于Sun的lib:

Bean01 bean01 = new Bean01();
bean01.setDefaultValues();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
new ObjectOutputStream( baos ).writeObject( bean01 );
System.out.println(Base64.encode(baos.toByteArray()));

这很好用.但是,我想使用org.apache.commons.codec.binary.base64执行相同的操作,但这不会返回相同的字符串:

System.out.println(org.apache.commons.codec.binary.Base64.encodeBase64(baos.toByteArray()));

使用Apache编码器实现byteArray的正确Base64编码的正确方法是什么？

Answer 1

实际上,commons-codec您使用的版本和特定的Sun内部版本会产生相同的结果.我认为你认为它们提供了不同的版本,因为你在执行时隐式调用toString()数组:

System.out.println(org.apache.commons.codec.binary.Base64.encodeBase64(baos.toByteArray()));

这绝对不会打印出数组内容.相反,它只会打印出数组引用的地址.

我编写了以下程序来相互测试编码器.您将从下面的输出中看到给出相同的结果:

import java.util.Random;

public class Base64Stuff
{
    public static void main(String[] args) {
        Random random = new Random();
        byte[] randomBytes = new byte[32];
        random.nextBytes(randomBytes);

        String internalVersion = com.sun.org.apache.xerces.internal.impl.dv.util.Base64.encode(randomBytes);
        byte[] apacheBytes =  org.apache.commons.codec.binary.Base64.encodeBase64(randomBytes);
        String fromApacheBytes = new String(apacheBytes);

        System.out.println("Internal length = " + internalVersion.length());
        System.out.println("Apache bytes len= " + fromApacheBytes.length());
        System.out.println("Internal version = |" + internalVersion + "|");
        System.out.println("Apache bytes     = |" + fromApacheBytes + "|");
        System.out.println("internal equal apache bytes?: " + internalVersion.equals(fromApacheBytes));
    }
}

以下是一系列的输出:

Internal length = 44
Apache bytes len= 44
Internal version = |Kf0JBpbxCfXutxjveYs8CXMsFpQYgkllcHHzJJsz9+g=|
Apache bytes     = |Kf0JBpbxCfXutxjveYs8CXMsFpQYgkllcHHzJJsz9+g=|
internal equal apache bytes?: true