获得下一个最小值,大于或等于每个组的给定值

Question

给出以下表1:

    RefID  intVal  SomeVal
    ----------------------
        1      10    val01
        1      20    val02
        1      30    val03
        1      40    val04
        1      50    val05
        2      10    val06
        2      20    val07
        2      30    val08
        2      40    val09
        2      50    val10
        3      12    val11
        3      14    val12
        4      10    val13
        5     100    val14
        5     150    val15
        5    1000    val16

和Table2包含一些RefID和intVals之类的

    RefID  intVal
    -------------
        1      11    
        1      28    
        2       9    
        2      50    
        2      51    
        4      11    
        5       1    
        5     150    
        5     151    

需要一个SQL语句来获取每个RefID的下一个更大的intValue和NULL,如果在Table1中找不到,则下面是预期的结果

    RefID  intVal  nextGt  SomeVal 
    ------------------------------
        1      11      20  val01
        1      28      30  val03
        2       9      10  val06
        2      50      50  val10
        2      51    NULL   NULL
        4      11    NULL   NULL
        5       1     100  val14
        5     150     150  val15
        5     151    1000  val16

帮助将不胜感激!

Answer 1

派生表a从table1 refid和intValtable2 中检索最小值; 外部查询仅检索someValue.

select a.refid, a.intVal, a.nextGt, table1.SomeVal
from
(
    select table2.refid, table2.intval, min (table1.intVal) nextGt
      from table2
      left join table1
        on table2.refid = table1.refid
       and table2.intVal <= table1.intVal
     group by table2.refid, table2.intval
) a
-- table1 is joined again to retrieve SomeVal 
left join table1
  on a.refid = table1.refid
 and a.nextGt = table1.intVal

这是Sql Fiddle的实时测试.