如何从Boost Spirit中的函数抛出expectation_failure?

Fra*_*ank 6 c++ boost boost-spirit boost-spirit-qi

在Boost :: Spirit中,如何expectation_failure从绑定的函数中触发Boost::Bind

背景:我解析包含复杂条目的大文件.当一个条目与前一个条目不一致时,我想失败并抛出一个expectation_failure(包含正确的解析位置信息).当我解析一个条目时,我绑定了一个函数,该函数决定该条目是否与之前看到的内容不一致.

我编写了一个小玩具示例,说明了这一点.在这里,我只是想抛出expectation_failureint10是不能分开的:

#include <iostream>
#include <iomanip>
#include <boost/spirit/include/qi.hpp>
#include <boost/bind.hpp>
#include <boost/spirit/include/classic_position_iterator.hpp>
namespace qi = boost::spirit::qi;
namespace classic = boost::spirit::classic;

void checkNum(int const& i) {
  if (i % 10 != 0) // >> How to throw proper expectation_failure? <<
    std::cerr << "ERROR: Number check failed" << std::endl;
}

template <typename Iterator, typename Skipper>
struct MyGrammar : qi::grammar<Iterator, int(), Skipper> {
  MyGrammar() : MyGrammar::base_type(start) {
    start %= qi::eps > qi::int_[boost::bind(&checkNum, _1)];
  }
  qi::rule<Iterator, int(), Skipper> start;
};

template<class PosIter>
std::string errorMsg(PosIter const& iter) {
  const classic::file_position_base<std::string>& pos = iter.get_position();
  std::stringstream msg;
  msg << "parse error at file " << pos.file
      << " line " << pos.line << " column " << pos.column << std::endl
      << "'" << iter.get_currentline() << "'" << std::endl
      << std::setw(pos.column) << " " << "^- here";
  return msg.str();
}

int main() {
  std::string in = "11";
  typedef std::string::const_iterator Iter;
  typedef classic::position_iterator2<Iter> PosIter;
  MyGrammar<PosIter, qi::space_type> grm;
  int i;
  PosIter it(in.begin(), in.end(), "<string>");
  PosIter end;
  try {
    qi::phrase_parse(it, end, grm, qi::space, i);
    if (it != end)
      throw std::runtime_error(errorMsg(it));
  } catch(const qi::expectation_failure<PosIter>& e) {
    throw std::runtime_error(errorMsg(e.first));
  }
  return 0;
}
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抛出一个expectation_failure意味着我在一个不能被10整除的int上得到这样的错误信息:

parse error at file <string> line 1 column 2
'11'
  ^- here
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sba*_*bbi 6

您可以在phoenix中使用_pass占位符来强制解析失败.这样的事情应该有效.

bool myfunc(int i) {return i%10 == 0;}

...
_int [ _pass = phoenix::bind(myfunc,_1)] 
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