PHP while循环只迭代一次

Question

快速问题;

$sql = mysql_query("SELECT * FROM cronjobs WHERE status = 0 ");

while($cronjob = mysql_fetch_array($sql)){
    if($cronjob['suid'] != $cronjob['cuid']){
        //echo 'not equal<br>';
        $set = 0;
        $sid = $cronjob['sid'];
        $suid = $cronjob['suid'];
        $cuid = $cronjob['cuid'];
        $set = notify($sid, $suid, $cuid);
        if($set==1){
            //echo 'notified<br>';
            $sql = "UPDATE cronjobs SET status = '1' WHERE id='".$cronjob['id']."'";
            if(mysql_query($sql)){
               echo '1<br>';
              $set = 0;
          }
        }
      }
   }
}

notify()将return 1(数字)

问题是即使有更多记录,也只执行while循环的一次迭代.我不知道这里有什么问题.帮帮我吧.

Answer 1

请将内部$ sql变量名更改为其他内容.outer $ sql和内部变量名正在发生冲突

$sql = mysql_query("SELECT * FROM cronjobs WHERE status = 0 ");

while($cronjob = mysql_fetch_array($sql)){
    if($cronjob['suid'] != $cronjob['cuid']){
        //echo 'not equal<br>';
        $set = 0;
        $sid = $cronjob['sid'];
        $suid = $cronjob['suid'];
        $cuid = $cronjob['cuid'];
        $set = notify($sid, $suid, $cuid);
        if($set==1){
            //echo 'notified<br>';
            $sql_2 = "UPDATE cronjobs SET status = '1' WHERE id='".$cronjob['id']."'";
            if(mysql_query($sql_2)){
               echo '1<br>';
              $set = 0;
          }
        }
      }
   }
}