PHP:使用mysql_fetch_assoc时遇到麻烦

use*_*544 0 php mysql

我试图从我的数据库返回结果,以便我可以创建一个XML文件,以便在Adobe Flex中使用,然后我将填充Google Map.目前使用Charles我收到以下错误mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource

这是我的函数的代码:

public function getBusiness ($item)
{
    $stmt = mysqli_prepare($this->connection,

    "SELECT * FROM businesses");

    $this->throwExceptionOnError();

    mysqli_stmt_execute($stmt);

    $this->throwExceptionOnError();

    $row = "";

    echo "<?xml version=\"1.0\" ?><map>";

    while(($row = mysql_fetch_assoc($stmt)) !== false)
    {
        echo "<business><businessid>" . $row["businessid"] . "</businessid>";
        echo "<type>" . $row["type"] . "</type>";
        echo "<name>" . $row["name"] . "</name>";
        echo "<street>" . $row["street"] . "</street>";
        echo "<city>" . $row["city"] . "</city>";
        echo "<country>" . $row["country"] . "</country>";
        echo "<postcode>" . $row["postcode"] . "</postcode>";
        echo "<latitude>" . $row["latitude"] . "</latitude>";
        echo "<longitude>" . $row["longitude"] . "</longitude>";
        echo "<phonenumber>" . $row["phonenumber"] . "</phonenumber>";
        echo "<email>" . $row["email"] . "</email>";
        echo "<website>" . $row["website"] . "</website>";
        echo "<logo>" . $row["logo"] . "</logo>";
        echo "<description>" . $row["description"] . "</description>";
        echo "<datesubmitted>" . $row["datesubmitted"] . "</datesubmitted></business>";
    }
    echo "</map>";


}
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任何人都可以帮忙吗?

Nie*_*sol 5

您是mysqli用来运行语句,然后尝试处理结果mysql?是的,那不行.

使用相同扩展名的功能!它们不是交叉兼容的.