我想实现一个符号类型,它跟踪我们已经拥有的符号(保存在其中_sym_table),如果它们存在则返回它们,否则创建新符号.代码:
# -*- coding: utf-8 -*-
_sym_table = {}
class Symbol(object):
def __new__(cls, sym):
if sym not in _sym_table:
return super().__new__(cls)
else:
return _sym_table[sym]
def __init__(self, sym):
self.sym = sym
_sym_table[sym] = self
def __str__(self):
return self.sym
def __cmp__(self, other):
return self is other
def __hash__(self):
return self.sym.__hash__()
Run Code Online (Sandbox Code Playgroud)
但是当我调用copy.deepcopy这样的Symbol实例列表时,会引发异常:
a = Symbol('a')
b = Symbol('b')
s = [a, b]
t = copy.deepcopy(s)
Run Code Online (Sandbox Code Playgroud)
错误消息:
Traceback (most recent call last):
File "xxx.py", line 7, in <module>
t = copy.deepcopy(s)
File "/usr/lib/python3.2/copy.py", line 147, in deepcopy
y = copier(x, memo)
File "/usr/lib/python3.2/copy.py", line 209, in _deepcopy_list
y.append(deepcopy(a, memo))
File "/usr/lib/python3.2/copy.py", line 174, in deepcopy
y = _reconstruct(x, rv, 1, memo)
File "/usr/lib/python3.2/copy.py", line 285, in _reconstruct
y = callable(*args)
File "/usr/lib/python3.2/copyreg.py", line 88, in __newobj__
return cls.__new__(cls, *args)
TypeError: __new__() takes exactly 2 arguments (1 given)
Run Code Online (Sandbox Code Playgroud)
所以我的问题是:
__new__方法对这些对象进行深层复制?copy.deepcopy?非常感谢!
一个问题是,deepcopy并且copy无法知道要传递给哪些参数__new__,因此它们只适用于不需要构造函数参数的类.
你可以拥有__init__参数的原因__init__是在复制对象时不会调用它,但__new__必须调用它来创建新对象.
所以如果你想控制复制,你必须定义特殊__copy__和__deepcopy__方法:
def __copy__(self):
return self
def __deepcopy__(self, memo):
return self
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
5192 次 |
| 最近记录: |