合并两个选择查询sql

Question

嘿,我正在使用oracle sql来创建数据库.

我现在正在处理查询,我想出了两个单独的quires,我想合并以获得结果.

我创建的第一个查询是查找演出所产生的总金额:

    SELECT SUM(bookings * CategoryPrice )AS Total_Money_Made
    FROM ( SELECT CategoryPrice , count(*) AS bookings
       FROM Booking b
       JOIN performance per
         ON b.performanceid =  per.performanceid
       JOIN Production p
         ON per.productionid = p.productionid          
      WHERE per.performanceid IN (1, 2, 3, 4)
      GROUP BY CategoryPrice)

这给了我一个结果:

TOTAL_MONEY_MADE

       337.5 

然后我有另一个查询,计算出总的特许金:

              SELECT SUM(ConsessionAmount * 2) AS Total_Consession_Money
      FROM( SELECT COUNT (*) AS ConsessionAmount
FROM Booking 
WHERE 
Consession = 'Yes' AND PerformanceID = '1' OR 
Consession = 'Yes' AND PerformanceID = '2' OR 
Consession = 'Yes' AND PerformanceID = '3' OR 
Consession = 'Yes' AND PerformanceID = '4' )

这给了我以下结果:

TOTAL_CONSESSION_MONEY

                18 

现在我想要一种方法,我可以从第一个查询中减去第二个查询的结果.可能吗？我该怎么办？我认为它与子查询有关,但我不太确定.

有帮助吗？谢谢.

Answer 1

你可以这样做:

WITH TOTAL_MADE
AS
(   
    SELECT SUM(bookings * CategoryPrice )AS Total_Money_Made
    FROM ( SELECT CategoryPrice , count(*) AS bookings
       FROM Booking b
       JOIN performance per
         ON b.performanceid =  per.performanceid
       JOIN Production p
         ON per.productionid = p.productionid          
      WHERE per.performanceid IN (1, 2, 3, 4)
      GROUP BY CategoryPrice)
), TOTAL_CONSESSION
AS
(
    SELECT SUM(ConsessionAmount * 2) AS Total_Consession_Money
      FROM( SELECT COUNT (*) AS ConsessionAmount
    FROM Booking 
    WHERE 
    Consession = 'Yes' AND PerformanceID = '1' OR 
    Consession = 'Yes' AND PerformanceID = '2' OR 
    Consession = 'Yes' AND PerformanceID = '3' OR 
    Consession = 'Yes' AND PerformanceID = '4' )
)
SELECT
    TOTAL_CONSESSION.Total_Consession_Money-
    TOTAL_MADE.Total_Money_Made AS Something
FROM
    TOTAL_MADE,
    TOTAL_CONSESSION;