getopt.h:在Windows中编译Linux C-Code

Question

getopt.h:在Windows中编译Linux C-Code

the*_*Sin 29 c build getopt command-line-arguments visual-studio

我试图在Windows下编译一组九个*.c文件(以及九个相关的*.h文件).

该代码最初是在Linux中设计的,用于使用标准GNU-Linux/C库"getopt.h"获取命令行参数.该库不适用于在Windows中构建C代码.

我想忽略我的代码现在所做的事情并提出以下问题.对于那些熟悉这个C库"getopt.h"的人:如果它依赖于POSIX风格的命令行参数,是否可以在Windows中构建和运行我的代码？或者我是否必须重新编写适用于Windows的代码,以不同方式传递输入文件(并放弃"getopt.h"依赖关系)？

Answer 1

bob*_*obo 36

getopt()实际上是一个非常简单的功能.我为它做了一个github要点,这里的代码也在下面

#include <string.h>
#include <stdio.h>

int     opterr = 1,             /* if error message should be printed */
  optind = 1,             /* index into parent argv vector */
  optopt,                 /* character checked for validity */
  optreset;               /* reset getopt */
char    *optarg;                /* argument associated with option */

#define BADCH   (int)'?'
#define BADARG  (int)':'
#define EMSG    ""

/*
* getopt --
*      Parse argc/argv argument vector.
*/
int
  getopt(int nargc, char * const nargv[], const char *ostr)
{
  static char *place = EMSG;              /* option letter processing */
  const char *oli;                        /* option letter list index */

  if (optreset || !*place) {              /* update scanning pointer */
    optreset = 0;
    if (optind >= nargc || *(place = nargv[optind]) != '-') {
      place = EMSG;
      return (-1);
    }
    if (place[1] && *++place == '-') {      /* found "--" */
      ++optind;
      place = EMSG;
      return (-1);
    }
  }                                       /* option letter okay? */
  if ((optopt = (int)*place++) == (int)':' ||
    !(oli = strchr(ostr, optopt))) {
      /*
      * if the user didn't specify '-' as an option,
      * assume it means -1.
      */
      if (optopt == (int)'-')
        return (-1);
      if (!*place)
        ++optind;
      if (opterr && *ostr != ':')
        (void)printf("illegal option -- %c\n", optopt);
      return (BADCH);
  }
  if (*++oli != ':') {                    /* don't need argument */
    optarg = NULL;
    if (!*place)
      ++optind;
  }
  else {                                  /* need an argument */
    if (*place)                     /* no white space */
      optarg = place;
    else if (nargc <= ++optind) {   /* no arg */
      place = EMSG;
      if (*ostr == ':')
        return (BADARG);
      if (opterr)
        (void)printf("option requires an argument -- %c\n", optopt);
      return (BADCH);
    }
    else                            /* white space */
      optarg = nargv[optind];
    place = EMSG;
    ++optind;
  }
  return (optopt);                        /* dump back option letter */
}

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