为什么抛出ApplicationException？

Question

我只是试验Mutex并编写了以下代码.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;

namespace Mutex_WaitOnewithTimeouts
{
    class Program
    {
        private static Mutex mut = new Mutex();
        private static int numOfThreads = 5;
        private static int numOfIterations = 3;
        private static Random rand = new Random();

        static void Main(string[] args)
        {
            Thread[] threads = new Thread[5];
            for (int num = 0; num < numOfThreads; num++)
            {
                threads[num] = new Thread(new ThreadStart(MyThreadProc));
                threads[num].Name = String.Format("Thread{0}", num);
                threads[num].Start();
            }
            Console.Read();
        }

        private static void MyThreadProc()
        {
            for (int iteration = 0; iteration < numOfIterations; iteration++)
            {
                UseResource();
            }
        }

        private static void UseResource()
        {
            Console.WriteLine("{0} accessing ", Thread.CurrentThread.Name);
            int time = (int)(rand.NextDouble() * 100);
            try
            {
                if (mut.WaitOne(time))
                {
                    Console.WriteLine("Yippie got mutex for {0}", Thread.CurrentThread.Name);
                    Thread.Sleep((int)rand.NextDouble() * 5000);
                }
                else
                {
                    Console.WriteLine("Nopee.... Timeout occured for {0}", Thread.CurrentThread.Name);
                }
            }
            catch (AbandonedMutexException ex)
            {
                Console.WriteLine(" Exception is caught");
            }
            finally 
            {
                Console.WriteLine("Releasing mutex for {0}", Thread.CurrentThread.Name);
               mut.ReleaseMutex();

            }

        }
    }
}

但是我有时会收到ApplicationException ..如果我的代码有任何问题,有人可以帮助我吗？请解释这个异常何时触发.

从不同步的代码块调用对象同步方法.在尝试释放互斥锁时,我在finally块中得到了这个.

Answer 1

即使您的WaitOne失败,您也将释放互斥锁.在您知道已获得互斥锁的if语句中移动ReleaseMutex调用.