制作临时表并从中进行选择

Question

当我运行这个时,我收到一个错误'未声明的变量:temp'

<?php 

$maketemp = "CREATE TEMPORARY TABLE temp(`itineraryId` int NOT NULL, `live` varchar(1), `shipCode` varchar(10), `description` text, `duration` varchar(10), PRIMARY KEY(itineraryId))"; 

mysql_query( $maketemp, $connection ) or die ( "Sql error : " . mysql_error ( ) );

$inserttemp = "SELECT live, id AS itineraryId, ship AS shipCode, description AS description, duration AS length FROM cruises WHERE live ='Y' INTO temp";

mysql_query( $inserttemp, $connection ) or die ( "Sql error : " . mysql_error ( ) );

$select = "SELECT intineraryId, shipCode, description, duration FROM temp";

$export = mysql_query ( $select, $connection ) or die ( "Sql error : " . mysql_error( ) );

有任何想法吗 ？

Answer 1

请不要mysql_*在新代码中使用函数.它们不再维护,并且已被正式弃用.看到红色的盒子？了解准备好的语句,并使用 PDO或 MySQLi -本文将帮助您确定哪些.如果您选择PDO,这是一个很好的教程.

这段代码应该有效:

<?php

  $maketemp = "
    CREATE TEMPORARY TABLE temp_table_1 (
      `itineraryId` int NOT NULL,
      `live` varchar(1),
      `shipCode` varchar(10),
      `description` text,
      `duration` varchar(10),
      PRIMARY KEY(itineraryId)
    )
  "; 

  mysql_query($maketemp, $connection) or die ("Sql error : ".mysql_error());

  $inserttemp = "
    INSERT INTO temp_table_1
      (`itineraryId`, `live`, `shipCode`, `description`, `duration`)
    SELECT `id`, `live`, `ship`, `description`, `duration`
    FROM `cruises`
    WHERE `live` = 'Y'
  ";

  mysql_query($inserttemp, $connection) or die ("Sql error : ".mysql_error());

  $select = "
    SELECT `itineraryId`, `shipCode`, `description`, `duration`
    FROM temp_table_1
  ";
  $export = mysql_query($select, $connection) or die ("Sql error : ".mysql_error());

我想你会用临时表做更多的东西,或者只是玩它,但如果不知道整个代码可以总结为:

<?php

  $query = "
    SELECT `id` AS 'itineraryId', `ship`, `description`, `duration`
    FROM `cruises`
    WHERE `live` = 'Y'
  ";
  $export = mysql_query($query, $connection) or die ("Sql error : ".mysql_error());