我试图计算以下三个结果的总和,但我只计算一个结果.
$sql = "(SELECT COUNT(*) FROM table1 WHERE somecondition)
UNION
(SELECT COUNT(*) FROM table2 WHERE somecondition)
UNION
(SELECT COUNT(*) FROM table3 WHERE somecondition)";
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任何人都可以帮忙.谢谢
您的查询将返回三行,其中包含三个单独的计数.
你想要的是什么
select sum(c) from (
(SELECT COUNT(*) AS c FROM table1 WHERE somecondition)
UNION
(SELECT COUNT(*) FROM table2 WHERE somecondition)
UNION
(SELECT COUNT(*) FROM table3 WHERE somecondition)
) all_three
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