Tam*_*ynh 5 cakephp model find conditional-statements
我有4个型号:
项目------ ----的hasMany>详细
项目------ ----的hasMany>收藏
项目------ ----的hasMany>分类
如何查找所有包含Favourite.member_id ='8'和Category.item_category_id ='1'的项目
这是我的Item模型关系:
public $hasMany = array(
'Detail' => array(
'className' => 'Detail',
'foreignKey' => 'item_id',
'dependent' => true,
'conditions' => '',
'order' => 'created DESC',
),
'Category' => array(
'className' => 'Category',
'foreignKey' => 'item_id',
'dependent' => true,
'conditions' => '',
'order' => 'created DESC',
),
'Favorite' => array(
'className' => 'Favorite',
'foreignKey' => 'item_id',
'dependent' => true,
'conditions' => '',
'order' => 'created DESC',
)
);
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我使用了这个查询(),没关系:
$this->set('test',$this->Item->query("SELECT items.*
FROM items, categories, favourites
WHERE items.id = items_item_categories.item_id
AND items.id = favorites.item_id
AND categories.item_category_id = 1 AND favourites.member_id = 8"));
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但我不喜欢使用query(),我把它改成find(),看起来不太好:
$this->set('test',$this->Item->find('all', array(
'contain'=>array(
'ItemDetail',
'Category'=>array('conditions'=>array('Category.item_category_id'=>1)),
'Favorite'=>array('conditions'=>array('Favorite.member_id'=>8)));
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CRO*_*OWD 11
您需要在模型上调用containsableBehaivor
<?php
class Item extends AppModel {
public $actsAs = array('Containable');
}
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在您的控制器中,您可以进行查询
$items = $this->Item->find('all', array(
'contain'=>array(
'ItemDetail',
'Category'=>array(
'conditions'=>array('Category.item_category_id'=>1)
),
'Favorite'=>array(
'conditions'=>array('Favorite.member_id'=>8)
)
)
);
$this->set('test', $items);
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尝试使用连接
$items = $this->Item->find('all', array(
'joins' => array(
array(
'table' => 'categories',
'alias' => 'Category',
'type' => 'inner',
'conditions'=> array('Category.item_category_id' => 1)
),
array(
'table' => 'favorites',
'alias' => 'Favorite',
'type' => 'inner',
'conditions'=> array('Favorite.member_id' => 8, 'Item.id = Favorite.item_id')
)
),
'contain'=>array('ItemDetail','Category','Favorite')
);
$this->set('test', $items);
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