Lor*_*ori 11 sqlite android join cursor android-contentprovider
我有一个ContentProvider允许LEFT OUTER JOIN在SQLite数据库上进行查询的Android .
让我们假设在数据库中我有3个表Users,Articles和Comments.该ContentProvider是类似以下内容:
public class SampleContentProvider extends ContentProvider {
private static final UriMatcher sUriMatcher;
public static final String AUTHORITY = "com.sample.contentprovider";
private static final int USERS_TABLE = 1;
private static final int USERS_TABLE_ID = 2;
private static final int ARTICLES_TABLE = 3;
private static final int ARTICLES_TABLE_ID = 4;
private static final int COMMENTS_TABLE = 5;
private static final int COMMENTS_TABLE_ID = 6;
private static final int ARTICLES_USERS_JOIN_TABLE = 7;
private static final int COMMENTS_USERS_JOIN_TABLE = 8;
// [...] other ContentProvider methods
@Override
public Cursor query(Uri uri, String[] projection, String selection, String[] selectionArgs, String sortOrder) {
String table = getTableName(uri);
// SQLiteWrapper is a wrapper class to manage a SQLiteHelper
Cursor c = SQLiteWrapper.get(getContext()).getHelper().getReadableDatabase()
.query(table, projection, selection, selectionArgs, null, null, sortOrder);
c.setNotificationUri(getContext().getContentResolver(), uri);
return c;
}
@Override
public Uri insert(Uri uri, ContentValues values) {
String table = getTableName(uri);
// SQLiteWrapper is a wrapper class to manage a SQLiteHelper
long id = SQLiteWrapper.get(getContext()).getHelper().getWritableDatabase()
.insert(table, null, values);
Uri itemUri = ContentUris.withAppendedId(uri, id);
getContext().getContentResolver().notifyChange(itemUri, null);
return itemUri;
}
private String getTableName(Uri uri) {
switch (sUriMatcher.match(uri)) {
case USERS_TABLE:
case USERS_TABLE_ID:
return "Users";
case ARTICLES_TABLE:
case ARTICLES_TABLE_ID:
return "Articles";
case COMMENTS_TABLE:
case COMMENTS_TABLE_ID:
return "Comments";
case ARTICLES_USERS_JOIN_TABLE:
return "Articles a LEFT OUTER JOIN Users u ON (u._id = a.user_id)";
case COMMENTS_USERS_JOIN_TABLE:
return "Comments c LEFT OUTER JOIN Users u ON (u._id = c.user_id)";
default:
throw new IllegalArgumentException("Unknown URI " + uri);
}
}
static {
sUriMatcher = new UriMatcher(UriMatcher.NO_MATCH);
sUriMatcher.addURI(AUTHORITY, "users", USERS_TABLE);
sUriMatcher.addURI(AUTHORITY, "articles", ARTICLES_TABLE);
sUriMatcher.addURI(AUTHORITY, "comments", COMMENTS_TABLE);
sUriMatcher.addURI(AUTHORITY, "users" + "/#", USERS_TABLE_ID);
sUriMatcher.addURI(AUTHORITY, "articles" + "/#", ARTICLES_TABLE_ID);
sUriMatcher.addURI(AUTHORITY, "comments" + "/#", COMMENTS_TABLE_ID);
sUriMatcher.addURI(AUTHORITY, "???", ARTICLES_USERS_JOIN_TABLE); // what uri here?
sUriMatcher.addURI(AUTHORITY, "???", COMMENTS_USERS_JOIN_TABLE); // what uri here?
}
}
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CursorAdapter每次在Users表中插入(或更新)行时,通知所有侦听已加入和未加入的查询的最佳URI方案是什么?
换句话说,如果我添加或更新表中的一个新行,我想送一个单一的通知,getContext().getContentResolver().notifyChange(itemUri, null)让所有的CursorAdapter在听我说话的任何查询(USERS_TABLE,ARTICLES_USERS_JOIN_TABLE,COMMENTS_USERS_JOIN_TABLE)收到通知,以更新他们的内容.
如果这是不可能的,是否有另一种方式通知所有观察者?
您可以使用特殊的Uri来查询:
sUriMatcher.addURI(AUTHORITY, "articlesusers", ARTICLES_USERS_JOIN_TABLE);
sUriMatcher.addURI(AUTHORITY, "commentsusers", COMMENTS_USERS_JOIN_TABLE);
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但我想不出发送单一通知的方法.看来你最好的选择是为每个引用被修改表的Uri发送通知.因此,您的insert/update/delete方法会多次调用notifyChange,具体取决于受影响的表.对于"用户"的更改,它将是3个通知 - 用户,文章用户和评论用户 - 因为它们都依赖于"用户"表.