Gho*_*gio 2 sorting api django sql-order-by tastypie
这是我的models.py
class Picture(models.Model):
image = models.ImageField(upload_to='uploads/')
caption = models.CharField(max_length=140, null=True, blank=True)
uploaded = models.DateField()
comments = models.ManyToManyField(Comment, null=True, blank=True)
Run Code Online (Sandbox Code Playgroud)
和我的tastypie的API资源,api.py:
class PictureResource(ModelResource):
class Meta:
queryset = Picture.objects.all.order_by('-uploaded')
resource_name = "photo"
authorization = Authorization()
API_LIMIT_PER_PAGE = 24
Run Code Online (Sandbox Code Playgroud)
如您所见,我希望我的API页面按照上传的最新图片顺序排列.
我的错误代码是:
函数对象没有属性'order_by'
通常我不知道该怎么做......
(顺便问一下,API_LIMIT_PER_PAGE = 24这是在正确的地方吗?)
将您更改queryset为:
class PictureResource(ModelResource):
class Meta:
queryset = Picture.objects.all().order_by('-uploaded')
resource_name = "photo"
authorization = Authorization()
API_LIMIT_PER_PAGE = 24
Run Code Online (Sandbox Code Playgroud)
all它本身只是一个方法,但如果你使用它all()就会返回一个QuerySet.order_by是一个QuerySet方法.
>> type(Picture.objects.all)
<type 'instancemethod'>
>> type(Picture.objects.all())
<class 'django.db.models.query.QuerySet'>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2529 次 |
| 最近记录: |