Nic*_*ati 5 python sorting design-patterns list
我想对每个字符串列表进行排序,例如:
list1 = ['3DT1_PN_DIS3D_S001', '3DT1_PN_noDIS3D_S001', '3DT1_S001', '3DT1_noPN_DIS3D_S001']
list2 = ['3DT1_noPN_DIS3D_S002', '3DT1_PN_noDIS3D_S002', '3DT1_PN_DIS3D_S002']
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遵循模式[ '3DT1_S##', '3DT1_noPN_DIS3D_S##', '3DT1_PN_noDIS3D_S##', '3DT1_PN_DIS3D_S##']
结果应该是:
list1 = [ '3DT1_S001', '3DT1_noPN_DIS3D_S001', '3DT1_PN_noDIS3D_S001', '3DT1_PN_DIS3D_S001']
list2 = [ '3DT1_noPN_DIS3D_S002', '3DT1_PN_noDIS3D_S002', '3DT1_PN_DIS3D_S002']
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我试着用排序方法玩了一下,但没有运气!
有什么帮助吗?
您可以定义一个按所需顺序返回元组的关键函数,然后将该函数传递给 的key参数,sorted如下所示。
>>> def key_fn(x):
... tags = x.split('_')
... if tags[1][0] == 'S':
... return (0, int(tags[1][1:]))
... elif tags[1] == 'noPN':
... return (1, int(tags[3][1:]))
... elif tags[1] == 'PN':
... if tags[2] == 'noDIS3D':
... return (2, int(tags[3][1:]))
... else:
... return (3, int(tags[3][1:]))
...
>>> list1 = ['3DT1_PN_DIS3D_S001', '3DT1_PN_noDIS3D_S001', '3DT1_S001', '3DT1_noPN_DIS3D_S001']
>>> sorted(list1, key=key_fn)
['3DT1_S001', '3DT1_noPN_DIS3D_S001', '3DT1_PN_noDIS3D_S001', '3DT1_PN_DIS3D_S001']
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