如何从actionscript创建SQL查询？

Question

如何从actionscript创建SQL查询？并呈现所有结果

Answer 1

您必须调用服务器端脚本(例如php),然后检索该脚本的输出

private var _loader:URLLoader;
private var _request:URLRequest;

private function loadData():void {
    _loader = new URLLoader();
    _request = new URLRequest("path/to/your/phpscript");
    _request.method = URLRequestMethod.POST;
    _loader.addEventListener(Event.COMPLETE, onLoadData);
    _loader.addEventListener(IOErrorEvent.IO_ERROR, onDataFailedToLoad);
    _loader.addEventListener(IOErrorEvent.NETWORK_ERROR, onDataFailedToLoad);
    _loader.addEventListener(IOErrorEvent.VERIFY_ERROR, onDataFailedToLoad);
    _loader.addEventListener(IOErrorEvent.DISK_ERROR, onDataFailedToLoad);
    _loader.load(_request);
}
private function onLoadData(e:Event):void {
    trace("onLoadData",e.target.data);
}
private function onDataFailedToLoad(e:IOErrorEvent):void {
    trace("onDataFailedToLoad:",e.text);
}

示例php脚本:

<?php

    // defining main variables
    $dbHost = "localhost";
    $dbUser = "root";
    $dbPass = "";
    $dbName = "test";
    $dbTable = "data";

    // connecting and selecting database
    @mysql_connect($dbHost, $dbUser, $dbPass) or die(mysql_error());
    @mysql_select_db($dbName) or die(mysql_error());

    // getting data
    $data = "";
    $res = mysql_query("SELECT * FROM ".$dbTable." ORDER BY id") or die(mysql_error());
    while($row = mysql_fetch_object($res)) {
        $data .= "nname=".$row->name.", ";
        $data .= "city=".$row->city;
    }
    echo $data;

?>

为了更好的工作流程,我建议调查AMF ......

这是关于AMF的教程