ani*_*ils 12 transactions sqlalchemy
我在我的项目中使用sql炼金术,我使用了db session,
engine = create_engine(configuration)
db_session = scoped_session(sessionmaker(autocommit=False,
autoflush=False,
bind=engine))
Base = declarative_base()
Base.query = db_session.query_property()
def init_db():
import models
Base.metadata.create_all(bind=engine)
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数据库会话用作:
db_session.merge(order) #order(model) in object
db_session.commit()
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现在我想将数据插入两个表的顺序和订单行项,所以我需要事务,如:1.在第一个插入中我希望插入的顺序的id在第二个插入查询中使用2.如果第二个插入查询失败,那么第一个查询应该回滚
Try:
#begin transaction/How to begin transaction?
order=db_session.add(order) #insert into order
#is need to commit db_session here as I need inserted orders id
#here actually db_session.commit() needed to get order's id(auto generated)
#if db_session committed here then sql alchemy starts new session
order_line_item.id = order.id
db_session.add(order_line_item) #insert into order line line item
db_session.commit()
#check transaction status if failed then rollback, How to check status?
except:
db_session.rollback()
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如何使用trasaction?
say*_*yap 18
根据Lafada的建议,嵌套交易不适用于这种情况.A flush()会做得很好,例如
db_session.begin()
try:
db_session.add(order)
db_session.flush()
order_line_item.id = order.id
db_session.add(order_line_item)
db_session.commit()
except:
db_session.rollback()
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或者更好的是,如果您在订单和订单项之间正确设置了关系,则您甚至不必费心手动分配ID.
您应该使用relationshipSQLAlchemy 的功能,因此您不必使用外键.例如,您的订单商品可能看起来像(我假设您有多方关系):
class OrderLineItem(Base):
id = Column(Integer, primary_key=True)
order_id = Column(Integer, ForeignKey('orders.id'))
order = relationship('Order', backref='order_line_items')
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在插入时,您只需分配订单实例:
order_line_item.order = order
session.add(order) # you even don't have to insert the item!
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请参阅教程中的更多详细信息:http://docs.sqlalchemy.org/en/latest/orm/relationships.html
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