Bra*_*esh 3 string perl comparison word-frequency
我是Perl的新手,我正在尝试写一个单词频率计数器作为学习练习.
但是,在我处理之后,我无法在下面的代码中找出错误.这是我的代码:
$wa = "A word frequency counter.";
@wordArray = split("",$wa);
$num = length($wa);
$word = "";
$flag = 1; # 0 if previous character was an alphabet and 1 if it was a blank.
%wordCount = ("null" => 0);
if ($num == -1) {
print "There are no words.\n";
} else {
print "$length";
for $i (0 .. $num) {
if(($wordArray[$i]!=' ') && ($flag==1)) { # start of a new word.
print "here";
$word = $wordArray[$i];
$flag = 0;
} elsif ($wordArray[$i]!=' ' && $flag==0) { # continuation of a word.
$word = $word . $wordArray[$i];
} elsif ($wordArray[$i]==' '&& $flag==0) { # end of a word.
$word = $word . $wordArray[$i];
$flag = 1;
$wordCount{$word}++;
print "\nword: $word";
} elsif ($wordArray[$i]==" " && $flag==1) { # series of blanks.
# do nothing.
}
}
for $i (keys %wordCount) {
print " \nword: $i - count: $wordCount{$i} ";
}
}
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它既不是"在这里"打印,也不是字.我并不担心此时的优化,尽管在这方面的任何输入也会受到高度赞赏.
这是一个很好的例子,如果你只是向它寻求帮助,Perl会帮助你找出问题所在.习惯于总是添加行:
use strict;
use warnings;
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到你的Perl程序的顶部.