如何在Java中创建链接列表数据结构？

Question

在Java中创建链表的最佳方法是什么？

Answer 1

熟悉Java的开发人员的明显解决方案是使用java.util中已经提供的LinkedList类.但是,假设您出于某种原因想要自己实现.下面是一个链接列表的快速示例,它在列表的开头插入一个新链接,从列表的开头删除并循环遍历列表以打印其中包含的链接.此实现的增强功能包括使其成为双链表,添加从中间或结尾插入和删除的方法,以及添加get和sort方法.

注意:在示例中,Link对象实际上不包含另一个Link对象 - nextLink实际上只是对另一个链接的引用.

class Link {
    public int data1;
    public double data2;
    public Link nextLink;

    //Link constructor
    public Link(int d1, double d2) {
        data1 = d1;
        data2 = d2;
    }

    //Print Link data
    public void printLink() {
        System.out.print("{" + data1 + ", " + data2 + "} ");
    }
}

class LinkList {
    private Link first;

    //LinkList constructor
    public LinkList() {
        first = null;
    }

    //Returns true if list is empty
    public boolean isEmpty() {
        return first == null;
    }

    //Inserts a new Link at the first of the list
    public void insert(int d1, double d2) {
        Link link = new Link(d1, d2);
        link.nextLink = first;
        first = link;
    }

    //Deletes the link at the first of the list
    public Link delete() {
        Link temp = first;
        if(first == null){
         return null;
         //throw new NoSuchElementException(); // this is the better way. 
        }
        first = first.nextLink;
        return temp;
    }

    //Prints list data
    public void printList() {
        Link currentLink = first;
        System.out.print("List: ");
        while(currentLink != null) {
            currentLink.printLink();
            currentLink = currentLink.nextLink;
        }
        System.out.println("");
    }
}  

class LinkListTest {
    public static void main(String[] args) {
        LinkList list = new LinkList();

        list.insert(1, 1.01);
        list.insert(2, 2.02);
        list.insert(3, 3.03);
        list.insert(4, 4.04);
        list.insert(5, 5.05);

        list.printList();

        while(!list.isEmpty()) {
            Link deletedLink = list.delete();
            System.out.print("deleted: ");
            deletedLink.printLink();
            System.out.println("");
        }
        list.printList();
    }
}

Answer 2

Java有一个LinkedList实现,您可能想要检查.您可以在java.sun.com下载JDK及其源代码.

Answer 3

使用java.util.LinkedList.像这样:

list = new java.util.LinkedList()

Answer 4

上面的链表显示方向相反.我认为插入方法的正确实现应该是

public void insert(int d1, double d2) { 
    Link link = new Link(d1, d2); 

    if(first==null){
        link.nextLink = null;
        first = link; 
        last=link;
    }
    else{
        last.nextLink=link;
        link.nextLink=null;
        last=link;
    }
} 

Answer 5

使用java.util.LinkedList要好得多,因为它可能比你要编写的更优化.

Answer 6

//slightly improved code without using collection framework

package com.test;

public class TestClass {

    private static Link last;
    private static Link first;

    public static void main(String[] args) {

        //Inserting
        for(int i=0;i<5;i++){
            Link.insert(i+5);
        }
        Link.printList();

        //Deleting
        Link.deletefromFirst();
        Link.printList();
    }


    protected  static class Link {
        private int data;
        private Link nextlink;

        public Link(int d1) {
            this.data = d1;
        }

        public static void insert(int d1) {
            Link a = new Link(d1);
            a.nextlink = null;
            if (first != null) {
                last.nextlink = a;
                last = a;
            } else {
                first = a;
                last = a;
            }
            System.out.println("Inserted -:"+d1);
        }

        public static void deletefromFirst() {
            if(null!=first)
            {
                System.out.println("Deleting -:"+first.data);
                first = first.nextlink;
            }
            else{
                System.out.println("No elements in Linked List");
            }
        }

        public static void printList() {
            System.out.println("Elements in the list are");
            System.out.println("-------------------------");
            Link temp = first;
            while (temp != null) {
                System.out.println(temp.data);
                temp = temp.nextlink;
            }
        }
    }
}