如果在验证后我决定将元素移回？如何设置jquery-ui draggable revert为true？

Question

我正在寻找一种方法来从恢复状态触发事件,如果某些事情没有验证,例如,如果元素存在,它将从另一个列表创建它,但如果它已经存在,它应该转到else并将元素返回到它原始位置:

$( "#catalog ul" ).droppable({
        tolerance: 'fit',
        activeClass: "ui-state-default",
        hoverClass: "ui-state-hover",
        accept: ":not(.ui-sortable-helper)",
        drop: function( event, ui ) {
            //check if already exists
            if($(this).find("#"+$(ui.draggable).attr("id")).length==0){
                $( "<li id="+$(ui.draggable).attr("id")+"></li>" ).text( ui.draggable.text() ).appendTo( this )
                .draggable({
                    revert: 'invalid',
                    stop: function(){
                        $(this).draggable('option','revert','invalid');
                    }
                }).droppable({
                    greedy: true,
                    tolerance: 'touch',
                    drop: function(event,ui){
                        ui.draggable.draggable('option','revert',true);
                    }
                });
            }else{
                //want to make the object go back by setting true to revert
                return false;
            }
        }
    })

Answer 1

谢谢Kenji,这确实有效:

ui.draggable.draggable('option','revert',true); 

我一直在努力争取一个早上,直到找到你的帖子,谢谢