获取数组中第一个条目的指针

Question

我想得到数组中第一个条目的指针.这就是我尝试的方式

int[] Results = { 1, 2, 3, 4, 5 };

unsafe
{
    int* FirstResult = Results[0];
}

获取以下编译错误.任何想法如何解决它？

您只能在固定语句初始值设定项中获取未固定表达式的地址

Answer 1

错误消息非常清楚.您可以参考MSDN.

unsafe static void MyInsaneCode()
{
    int[] Results = { 1, 2, 3, 4, 5 };
    fixed (int* first = &Results[0]) { /* something */ }
}

Answer 2

试试这个:

unsafe
{
    fixed (int* FirstResult = &Results[0])
    {

    }
}

Answer 3

错误代码是获得答案的神奇之处 - 搜索错误代码(在您的情况下为CS0212),并且在很多情况下您会得到建议修复的解释.

搜索:http://www.bing.com/search？q = CS0212 + msdn

结果:http: //msdn.microsoft.com/en-us/library/29ak9b70%28v=vs.90%29.aspx

页面代码:

   unsafe public void mf()
   {
      // Null-terminated ASCII characters in an sbyte array 
      sbyte[] sbArr1 = new sbyte[] { 0x41, 0x42, 0x43, 0x00 };
      sbyte* pAsciiUpper = &sbArr1[0];   // CS0212
      // To resolve this error, delete the previous line and 
      // uncomment the following code:
      // fixed (sbyte* pAsciiUpper = sbArr1)
      // {
      //    String szAsciiUpper = new String(pAsciiUpper);
      // }
   }