If-Else条件内的光标不起作用

Question

我有一个程序,我需要检查表中的状态,该状态存在于其他服务器中,需要更新它.

这是我的存储过程..请检查

ALTER PROCEDURE [dbo].[testproceudre]    
AS       
DECLARE @Status INT     
DECLARE @UpdatedDateTime DATETIME    
DECLARE @STSFLG INT    
--dynamic query variables       

DECLARE @SQLString NVARCHAR(4000)     
DECLARE @ParmDefinition NVARCHAR(4000)     
DECLARE @DBSTRING VARCHAR(1000)     
DECLARE @TABLESTR VARCHAR(200)       
BEGIN     

 SET @DBSTRING = '[server name].[db name]'        
 SET @TABLESTR = ''     

 DECLARE @SYSproUploadflag INT    
 DECLARE @DpCodeExist INT    

 SET @SYSproUploadflag = 0     
 SET @DpCodeExist = 0     
 SET @TABLESTR = @DBSTRING+'.[dbo].[otherservertablename]'     
 SET @ParmDefinition = N'@Status INT,@UpdatedDateTime DATETIME'    
 SET @SQLString ='SELECT StatusFlg,ConfirmedDate FROM localtablename
 JOIN '+ @TABLESTR +' ON     
 IssuesId=SFAIssueId WHERE Statusflg=4'     

 EXECUTE sp_executesql     
 @SQLString,     
 @ParmDefinition,     
 @Status = @Status,     
 @UpdatedDateTime = @UpdatedDateTime     
 BEGIN     
     ------------------------------------------------------------------------  
  IF @SYSproUploadflag = 0     
  BEGIN  
   DECLARE PARKCURSOR CURSOR FOR 
   SELECT STATUS FROM [server name].[db name].[dbo].[otherservertablename]
   JOIN localtablename ON SFAISSUEID = ISSUESID
   OPEN  PARKCURSOR
   FETCH NEXT FROM PARKCURSOR 
   INTO @STSFLG
   WHILE (@@FETCH_STATUS = 0)
   BEGIN
        IF(@STSFLG = 3)
        BEGIN
           UPDATE issue2 SET status = 4,UpdatedDateTime=ConfirmedDate,
           SOURCEOFUPDATION = 'SFA'     
           FROM [server name].[db name].[dbo].[otherservertablename] issue2  JOIN     
           tblAHCIssues issue1    
           ON issue2.sfaissueid=issue1.issuesid 
        END
        IF(@STSFLG = 2)
        BEGIN
           UPDATE issue2 SET status = 7,UpdatedDateTime=ConfirmedDate,
           SOURCEOFUPDATION = 'SFA'     
           FROM [server name].[db name].[dbo].[otherservertablename] issue2  JOIN     
           localtablename issue1    
           ON issue2.sfaissueid=issue1.issuesid  
        END  
        FETCH NEXT FROM PARKCURSOR INTO  @STSFLG 
   END
    CLOSE PARKCURSOR 
    DEALLOCATE PARKCURSOR 
  END     
 END        
END     

我的问题是,如果状态为2,则所有行中的状态为2,如果所有行中的状态为3,则更新为4但如果有些为3且有些为2,则第一行是什么,相对于只有它正在更新所有的值.这意味着如果第一行的状态为3,第二行的状态为2,它将两者都更新为4.但是它应该首先更新为4,第二行更新为7.可以任何一个帮助我,我正在做什么错误???

Answer 1

您的更新中没有where子句 - 每个更新都将更新完全相同的行集(即issuetable中存在匹配问题的issue2中的所有行).

这意味着最终结果将取决于光标中的最后一个状态ID.