InP*_*uit 14 jpa composite-key playframework ebean playframework-2.0
我有一个名为"EventCheckin"的模型,它具有到"事件"和"用户"的ManyToOne映射."EventCheckin"表的PrimaryKey是用户的id和事件的id.我试图在我的EventCheckin模型中使用"EmbeddedId"来表示这一点,但是当我尝试保存EventCheckin时,它会尝试将user_id和event_id值放入表中两次,这显然会失败:
Caused by: org.h2.jdbc.JdbcSQLException: Duplicate column name "USER_ID"; SQL statement:
insert into eventCheckin (event_id, user_id, latitude, longitude, user_id, event
_id) values (?,?,?,?,?,?) [42121-158]
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EventCheckin课程:
@Entity
@Table(name="eventCheckin")
public class EventCheckin extends Model
{
@EmbeddedId public CheckinId id;
@MapsId("userId")
@JoinColumn(name="user_id")
@ManyToOne public User user;
@MapsId("eventId")
@JoinColumn(name="event_id")
@ManyToOne public Event event;
.....
}
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CheckinId EmbeddedId类::
@Embeddable
public class CheckinId implements Serializable
{
public Long eventId;
public String userId;
.....
}
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我的EventCheckin数据库表定义如下:
create table eventCheckin (
user_id varchar(255) not null,
event_id bigint not null,
latitude float,
longitude float,
constraint pk_eventCheckIn primary key (user_id,event_id),
foreign key (user_id) references user (email),
foreign key (event_id) references event (id)
);
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看来您尝试通过 @MapsId 和 @EmbeddedId 做同样的事情。一种(可行的)选择是选择 IdClass(等于、哈希码、额外属性等被删除):
@Entity
public class User {
@Id public String id;
}
@Entity
public class Event {
@Id public long id;
}
public class CheckinId implements Serializable {
public Long event;
public String user;
}
@Entity
@IdClass(CheckinId.class)
@Table(name="eventCheckin")
public class EventCheckin {
@Id
@JoinColumn(name="user_id")
@ManyToOne public User user;
@Id
@JoinColumn(name="event_id")
@ManyToOne public Event event;
}
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