使用C++,如何从派生类方法调用基类方法并将其应用于作为参数传递的对象？

Question

我无法弄清楚如何从派生类方法调用基类方法,但同时在作为参数传递的对象上应用此方法调用.

我的意思是:

class Animal
{ 
    virtual void eat(Animal& to_be_eaten) = 0;
 };

class Carnivores: public Animal
{ 
    virtual void eat(Animal& to_be_eaten) { /*implementation here*/}

};

class Wolf : public Carnivores
{ 
    virtual void eat(Animal& to_be_eaten)
    { /*call eat method(of Base class) of Base to_be_eaten here*/ }
 }

我想到了这样的事情

 dynamic_cast<Carnivores&>(to_be_eaten).eat(*this) //and got a segmentation fault

有没有办法做到这一点？

谢谢!

新编辑::更新了代码

Answer 1

很简单:

class Derived : public Base  {
    virtual void eat(Animal& to_be_eaten) { 
        Base::eat(to_be_eaten);
        // do anything you want with to_be_eaten here.
    }
};

编辑:这对我有用:

class Animal
{ 
    virtual void eat(Animal& to_be_eaten) = 0;
 };

class Carnivores: public Animal
{ 
    virtual void eat(Animal& to_be_eaten) { /*implementation here*/}

};

class Wolf : public Carnivores
{ 
    virtual void eat(Animal& to_be_eaten)
    { 
        Carnivores *c = dynamic_cast<Carnivores*>(&to_be_eaten);
        if(c) 
            c->Carnivores::eat(*this);
    }
 }

请注意,我必须Base::eat公开才能从中调用它Derived.