用于将XML文件读入DataTable的代码

Muk*_*Ran 4 c# xml datatable

我编写了下面的代码片段,它读取给定的xml文件并将内容写入数据表.请不要建议使用LinqToXml,因为这是一个遗留应用程序.

            // create the DataTable that will hold the data
            DataTable table = new DataTable("ListOfPersonsWithInfo");


            // open the file using a Stream
            using (Stream stream = new FileStream(fileNameWithAbsolutePath, FileMode.Open, FileAccess.Read))
            {
                // create the table with the appropriate column names
                table.Columns.Add("Name", typeof(String));
                table.Columns.Add("ImagePath", typeof(String));
                table.Columns.Add("Address", typeof(String));

                // use ReadXml to read the XML stream
                table.ReadXml(stream);

                // tried with this overload-option as well but didnt help
                //table.ReadXml(fileNameWithAbsolutePath);

                // return the results
                return table;
            }
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但是返回的表包含ZERO行...... !!! 其中实际的xml文件有'3行',结构如下(任何IDEA这里出了什么问题?):

<?xml version="1.0" encoding="utf-8"?>
<Details>
    <EachPerson>
        <Name>Jack</Name>
        <ImagePathAndFileName>C:\Users\Public\Pictures\Sample Pictures\Desert.jpg</ImagePathAndFileName>
        <Address>NewYork</Address>
    </EachPerson>
    <EachPerson>
        <Name>Tom</Name>
        <ImagePathAndFileName>C:\Users\Public\Pictures\Sample Pictures\Desert.jpg</ImagePathAndFileName>
        <Address>London</Address>
    </EachPerson>
    <EachPerson>
        <Name>Jill</Name>
        <ImagePathAndFileName>C:\Users\Public\Pictures\Sample Pictures\Desert.jpg</ImagePathAndFileName>
        <Address>Tokyo</Address>
    </EachPerson>
</Details>
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Pra*_*enu 11

您可以使用ReadXML

        DataSet ds = new DataSet();
        ds.ReadXml(fileNameWithAbsolutePath);
        return ds.Tables[0];
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