Was*_*han 12 java android file filenotfoundexception
我只想创建一个像这样的File对象
File myImageFile = new File ("image1") ;
但它给了我FileNotFoundException的例外我
如何引用我的原始文件夹中的文件
编辑: 其实我想做这样的事情
MultipartEntity multipartEntity= new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
multipartEntity.addPart("uploaded", new FileBody(new File("myimage")));
通常,您通过getResources().openRawResource(R.id._your_id)访问文件.如果您绝对需要文件引用,可以选择将其复制到内部存储:
File file = new File(this.getFilesDir() + File.separator + "DefaultProperties.xml");
try {
InputStream inputStream = resources.openRawResource(R.id._your_id);
FileOutputStream fileOutputStream = new FileOutputStream(file);
byte buf[]=new byte[1024];
int len;
while((len=inputStream.read(buf))>0) {
fileOutputStream.write(buf,0,len);
}
fileOutputStream.close();
inputStream.close();
} catch (IOException e1) {}
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现在File,您可以随时随地访问它.
这里有2个函数。一份从 RAW 读取,一份从 Assets 读取
/**
* Method to read in a text file placed in the res/raw directory of the
* application. The method reads in all lines of the file sequentially.
*/
public static void readRaw(Context ctx,int res_id) {
InputStream is = ctx.getResources().openRawResource(res_id);
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr, 8192); // 2nd arg is buffer
// size
// More efficient (less readable) implementation of above is the
// composite expression
/*
* BufferedReader br = new BufferedReader(new InputStreamReader(
* this.getResources().openRawResource(R.raw.textfile)), 8192);
*/
try {
String test;
while (true) {
test = br.readLine();
// readLine() returns null if no more lines in the file
if (test == null)
break;
}
isr.close();
is.close();
br.close();
} catch (IOException e) {
e.printStackTrace();
}
}
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并从资产文件夹
/**
* Read a file from assets
*
* @return the string from assets
*/
public static String getQuestions(Context ctx,String file_name) {
AssetManager assetManager = ctx.getAssets();
ByteArrayOutputStream outputStream = null;
InputStream inputStream = null;
try {
inputStream = assetManager.open(file_name);
outputStream = new ByteArrayOutputStream();
byte buf[] = new byte[1024];
int len;
try {
while ((len = inputStream.read(buf)) != -1) {
outputStream.write(buf, 0, len);
}
outputStream.close();
inputStream.close();
} catch (IOException e) {
}
} catch (IOException e) {
}
return outputStream.toString();
}
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