如何使用std :: mem_fun传递参数

Question

我想知道是否有办法使用std :: mem_fun传递参数？我想确切地说,我可以拥有尽可能多的参数和许多成员函数.
问题是我的标准很旧而且我正在寻找一个完整的标准方式,因此即使我知道我可以轻松地做到这一点,也不允许提升作为答案= /

以下是我想如何使用它的一个小例子:

#include <list>
#include <algorithm>

// Class declaration
//
struct Interface {
   virtual void run() = 0;
   virtual void do_something(int) = 0;
   virtual void do_func(int, int) = 0;
};

struct A : public Interface {
   void run() { cout << "Class A : run" << endl; }
   void do_something(int foo) { cout << "Class A : " << foo << endl; }
   void do_func(int foo, int bar) { cout << "Class A : " << foo << " " << bar << endl; }
};

struct B : public Interface {
   void run() { cout << "Class B : run" << endl; }
   void do_something(int foo) { cout << "Class B : " << foo << endl; }
   void do_func(int foo, int bar) { cout << "Class B : " << foo << " " << bar << endl; }
};

// Main
//
int main() {
   // Create A and B
   A a;
   B b;

   // Insert it inside a list
   std::list<Interface *> list;
   list.push_back(&a);
   list.push_back(&b);

   // This works
   std::for_each(list.begin(), list.end(), std::mem_fun(&Interface::run));

   // But how to give arguments for those member funcs ?
   std::for_each(list.begin(), list.end(), std::mem_fun(&Interface::do_something));
   std::for_each(list.begin(), list.end(), std::mem_fun(&Interface::do_func));
   return 0;
}

Answer 1

使用std::bind通过std::bind1st和std::bind2nd

std::for_each(list.begin(), list.end(),
              std::bind2nd(std::mem_fun(&Interface::do_something),1) // because 1st is this
             );

不幸的是,该标准对两个参数版本没有帮助,你需要编写自己的:

struct MyFunctor
{
    void (Interface::*func)(int,int);
    int         a;
    int         b;

    MyFunctor(void (Interface::*f)(int,int), int a, int b): func(f), a(a), b(b) {}

    void operator()(Interface* i){ (i->*func)(a,b);}
};

std::for_each(list.begin(), list.end(),
              MyFunctor(&Interface::do_func, 1, 2)
             );