错误C2440:'=':无法从'Node <ValueType>*'转换为'Node <ValueType>*'

Question

我正在做家庭作业,我们不允许使用任何STL容器.我对LinkedList的实现是一系列与指针链接在一起的节点.我有另一个名为ContinuousList的类,它有一个数据成员LinkedList,其节点包含指向各种其他LinkedLists中的节点的指针.我正在尝试将一个返回指向Node的指针的函数的返回值赋给一个变量,该变量也是指向Node的指针,但它说这是无效的,我不明白为什么我不能做那.

template <typename ValueType>
struct Node
{
    Node();
    std::string m_key;
    ValueType m_value;
    Node<ValueType>* m_next;
};

链表类:

template <typename ValueType>
class LinkedList
{
public:
    Node<ValueType>* begin()
    {
        return m_head;
    }
private:
    Node<ValueType>* m_head;
};

ContinuousList:

template <typename ValueType>
class ContinuousList
{
public:
    ValueType* iterate(std::string& key)
    {
        m_curr = m_collection.begin(); // Error occurs here

        ...
    }
private:
    LinkedList<Node<ValueType>*> m_collection;
    Node<ValueType>* m_curr;
};

完整的错误消息

1>          error C2440: '=' : cannot convert from 'Node<ValueType> *' to 'Node<ValueType> *'
1>          with
1>          [
1>              ValueType=Node<bool> *
1>          ]
1>          and
1>          [
1>              ValueType=bool
1>          ]
1>          Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
1>          while compiling class template member function 'bool *ContinuousList<ValueType>::iterate(std::string &)'
1>          with
1>          [
1>              ValueType=bool
1>          ]
1>          see reference to class template instantiation 'ContinuousList<ValueType>' being compiled
1>          with
1>          [
1>              ValueType=bool
1>          ]

Answer 1

    LinkedList<Node<ValueType>*> m_collection;

这个

让m_head成为

      Node<Node<ValueType>*>*

这不是你想要的.

    m_curr = m_collection.begin()
    Node<ValueType> = Node<Node<ValueType>*>*

如果

    Node<Node<ValueType>*>* 

是你想要的,使用

m_collection.begin() - > m_value;

或使用

    LinkedList<ValueType>, 

它将返回Node

虽然我可能真的很累.... = D.