处理Ajax请求和响应zend框架

Question

我想向控制器发送Ajax请求,我在客户端这样做

jQuery.ajax({
    url: "public/visits/visit/get-visits",
    type: "POST",
    dataType: 'json',
    data: data,
    success: function(data){
        alert(data)
    },
    error:function(){
        alert("fail :(");
    }
});

在服务器端,我处理请求作为其他请求

public function getVisitsAction() {
if (isset($_POST)) {
    $mapper = new Visits_Model_VisitsMapper();
    $allVisits = $mapper->getAllVisits();
    echo json_encode($allVisits);
 }

当我调用该操作时,会发生失败警报,当我通过防火错误检查出来时,我发现它将json数据返回给客户端到页面get-visit.phtml.

如何从发送json请求的页面处理成功函数中的响应并将其重定向到get-visit.phtml页面？

Answer 1

Zend有Zend_Controller_Action_Helper_Json执行以下操作:

$this->_helper->layout()->disableLayout();
$this->_helper->viewRenderer->setNoRender(true);
echo json_encode($allVisits);
exit;

所以它可能更简单:

public function getVisitsActions() {
    if ($this->getRequest()->isXmlHttpRequest()) {
        if ($this->getRequest()->isPost()) {
            $mapper = new Visits_Model_VisitsMapper();

            $this->_helper->json($mapper->getAllVisits());
        }
    }
    else {
        echo 'Not Ajax';
        // ... Do normal controller logic here (To catch non ajax calls to the script)
    }
}

Answer 2

为了更正确的方式这样做.我会在你的控制器中使用以下内容

public function getVisitsActions() {
    if ($this->getRequest()->isXmlHttpRequest()) {
        if ($this->getRequest()-isPost()) {

            $mapper = new Visits_Model_VisitsMapper();
            $allVisits = $mapper->getAllVisits();

            $this->_helper->layout()->disableLayout();
            $this->_helper->viewRenderer->setNoRender(true);
            echo json_encode($allVisits);
            exit;
        }
    }
    else {
        // ... Do normal controller logic here (To catch non ajax calls to the script)
    }
}