如何使用jQuery.grep()过滤多维JSON对象

Question

我有一个JSON对象,如下所示:

{"data":
 [
  {"name":"Alan","height":"171","weight":"66"},
  {"name":"Ben","height":"182","weight":"90"},
  {"name":"Chris","height":"163","weight":"71"}
 ]
 ,"school":"Dover Secondary"
}

我想过滤JSON对象以获取高于170且重于70的数据,然后对此对象进行排序.在jQuery网站上,我了解过在线性阵列上很容易实现过滤,例如:

arr = jQuery.grep(arr, function(element, index){
  return (element > 70 && index = 'weight');
});

如何同时过滤重量和高度以获得:

{"data":
 [
  {"name":"Ben","height":"182","weight":"90"},
 ]
 ,"school":"Dover Secondary"
}

Answer 1

我想你的意思是:http://jsfiddle.net/NRuM7/1/.

var obj = {"data":
 [
  {"name":"Alan","height":"171","weight":"66"},
  {"name":"Ben","height":"182","weight":"90"},
  {"name":"Chris","height":"163","weight":"71"}
 ]
 ,"school":"Dover Secondary"
};

obj.data = jQuery.grep(obj.data, function(element, index){
  return element.weight > 70 && element.height > 170; // retain appropriate elements
});