在Django模板中的字典

Question

我有这样的观点:

info_dict =  [{u'Question 1': ['13365', '13344']}, {u'Question 2': ['13365']}, {u'Question 3': []}]

for key in info_dict:
    for k, v in key.items():
        profile = User.objects.filter(id__in=v, is_active=True)
    for f in profile:
        wanted_fields = ['job', 'education', 'country', 'city','district','area']
        profile_dict = {}
        for w in wanted_fields:
            profile_dict[f._meta.get_field(w).verbose_name] = getattr(f, w).name

return render_to_response('survey.html',{
    'profile_dict':profile_dict,
},context_instance=RequestContext(request))

并在模板中:

<ul>
    {% for k, v in profile_dict.items %}
        <li>{{ k }} : {{ v }}</li>
    {% endfor %}
</ul>

模板中只有一个字典.但是4个字典可能在这里(因为info_dict)在视图中出了什么问题？

提前致谢

Answer 1

在您的视图中,您只创建了一个变量(profile_dict)来保存配置文件dicts.

在循环的每次迭代中for f in profile,您将重新创建该变量,并使用新字典覆盖其值.因此,当您profile_dict在传递给模板的上下文中包含它时,它将保留分配给的最后一个值profile_dict.

如果要将四个profile_dicts传递给模板,可以在视图中执行以下操作:

info_dict =  [{u'Question 1': ['13365', '13344']}, {u'Question 2': ['13365']}, {u'Question 3': []}]

# Create a list to hold the profile dicts
profile_dicts = []

for key in info_dict:
    for k, v in key.items():
        profile = User.objects.filter(id__in=v, is_active=True)
    for f in profile:
        wanted_fields = ['job', 'education', 'country', 'city','district','area']
        profile_dict = {}
        for w in wanted_fields:
            profile_dict[f._meta.get_field(w).verbose_name] = getattr(f, w).name

        # Add each profile dict to the list
        profile_dicts.append(profile_dict)

# Pass the list of profile dicts to the template
return render_to_response('survey.html',{
    'profile_dicts':profile_dicts,
},context_instance=RequestContext(request))

然后在你的模板中:

{% for profile_dict in profile_dicts %}
<ul>
    {% for k, v in profile_dict.items %}
        <li>{{ k }} : {{ v }}</li>
    {% endfor %}
</ul>
{% endfor %}