使用g ++编译C++文件时出错

Question

我正在使用来自cygwin的g ++,我正在尝试编译一个.cpp文件,但我遇到了一个错误,

这是代码:

#include "randomc.h"
#include <time.h>             // Define time() 
#include <stdio.h>            // Define printf() 
#include <cstdlib>



int main(int argc, char *argv[] ) {
int seed = atoi(argv[1]);
int looptotal = atoi(argv[2]);

//initializes rng, I want to use argv[1] to set seed 
void CRandomMother::RandomInit (int seed) {
int i;
// loop for the amount of times set by looptotal and return random number
for (i = 0; i < looptotal; i++) {
double s;
s = Random();
printf("\n%f", s)
}

}
return 0;

}

这是我在尝试使用cygwin终端和g ++进行编译时遇到的错误

Administrator@WIN-19CEL322IRP /cygdrive/c/xampp/xampp/htdocs$  g++ ar.cpp -o prog
ar.cpp: In function `int main(int, char**)':
ar.cpp:13: error: a function-definition is not allowed here before '{' token
ar.cpp:13: error: expected `,' or `;' before '{' token

.cpp文件和头文件randomc.h位于我的xampp位置.我认为这根本不重要,不是吗？有人能告诉我如何编译并运行吗？谢谢.

Answer 1

将函数定义移到外面main:

//initializes rng, I want to use argv[1] to set seed 
void CRandomMother::RandomInit (int seed, int looptotal) {
   int i;
   // loop for the amount of times set by looptotal and return random number
   for (i = 0; i < looptotal; i++) {
      double s;
      s = Random();
      printf("\n%f", s)
   }
}

int main(int argc, char *argv[] ) {
   int seed = atoi(argv[1]);
   int looptotal = atoi(argv[2]);
   return 0;
}

错误消息对我来说非常清楚.

在C++中,您不允许在另一个函数中定义函数.