如何从所选Listview项目中设置上下文菜单的标题?以下是我的主要活动.
public class OListActivity extends ListActivity {
......
......
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
registerForContextMenu(getListView());
......
......
MatrixCursor cursor;
cursor = NameManager.getnameList();
startManagingCursor(cursor);
String[] from = { "name", "info", "status", BaseColumns._ID };
int[] to = { R.id.name, R.id.info, R.id.status };
SimpleCursorAdapter adapter = new SimpleCursorAdapter(this,
R.layout.row, cursor, from, to);
setListAdapter(adapter);
}
@Override
public void onCreateContextMenu(ContextMenu menu, View v,
ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
menu.setHeaderTitle("Menu");// TODO Change to name of selected listview item.
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.context_menu, menu);
}
.....
.....
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我需要设置menu.setHeaderTitle为R.id.name.我知道另一个similer 问题,但它没有提到处理ListView具有多个textview 的复杂问题.
Luk*_*rog 14
使用方法中的ContextMenuInfo参数onCreateContextMenu():
@Override
public void onCreateContextMenu(ContextMenu menu, View v,
ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
AdapterView.AdapterContextMenuInfo info;
try {
// Casts the incoming data object into the type for AdapterView objects.
info = (AdapterView.AdapterContextMenuInfo) menuInfo;
} catch (ClassCastException e) {
// If the menu object can't be cast, logs an error.
Log.e(TAG, "bad menuInfo", e);
return;
}
Cursor cursor = (Cursor) getListAdapter().getItem(info.position);
if (cursor == null) {
// For some reason the requested item isn't available, do nothing
return;
}
// if your column name is "name"
menu.setHeaderTitle(cursor.getString(cursor.getColumnIndex("name")));
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.context_menu, menu);
}
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