使用多行命令参数批量启动PowerShell

Question

我想将几行代码从批处理文件传递给powershell.exe as -command参数.

例如,代码如下:

SET LONG_COMMAND=
if ($true)
{
Write-Host "Result is True"
}
else
{
Write-Host "Result is False"
}

START Powershell -noexit -command "%LONG_COMMAND%"

我想这样做而不创建PowerShell脚本文件,只创建一个批处理文件.
可能吗？

谢谢.

Answer 1

您可以添加"^"以继续分配给变量的字符串.这会将命令创建为一行,因此您需要使用';' 之间的陈述:

@ECHO off
SET LONG_COMMAND= ^
if ($true) ^
{ ^
Write-Host "Result is True"; ^
Write-Host "Multiple statements must be separated by a semicolon." ^
} ^
else ^
{ ^
Write-Host "Result is False" ^
}

START Powershell -noexit -command %LONG_COMMAND%

如果您需要执行的唯一代码是PowerShell,您可以使用以下内容:

;@Findstr -bv ;@F "%~f0" | powershell -command - & goto:eof

if ($true){
    Write-Host "Result is True" -fore green
}
else{
    Write-Host "Result is False" -fore red
}

Start-Sleep 5

它将所有不以"; @F"开头的行传递给PowerShell.

编辑:我能够在单独的窗口中启动PowerShell并允许cmd退出:

@@ECHO off
@@setlocal EnableDelayedExpansion
@@set LF=^


@@SET command=#
@@FOR /F "tokens=*" %%i in ('Findstr -bv @@ "%~f0"') DO SET command=!command!!LF!%%i
@@START powershell -noexit -command !command! & goto:eof

if ($true){
    Write-Host "Result is True" -fore green
}
else{
    Write-Host "Result is False" -fore red
}

请注意,设置'LF'变量后必须有2个空格,因为我们正在为变量分配换行符.

Answer 2

使用

start powershell -NoExit -EncodedCommand "aQBmACAAKAAkAHQAcgB1AGUAKQAKAHsACgBXAHIAaQB0AGUALQBIAG8AcwB0ACAAIgBSAGUAcwB1AGwAdAAgAGkAcwAgAFQAcgB1AGUAIgAKAH0ACgBlAGwAcwBlAAoAewAKAFcAcgBpAHQAZQAtAEgAbwBzAHQAIAAiAFIAZQBzAHUAbAB0ACAAaQBzACAARgBhAGwAcwBlACIACgB9AAoA"

引自 powershell /?

# To use the -EncodedCommand parameter:
$command = 'dir "c:\program files" '
$bytes = [System.Text.Encoding]::Unicode.GetBytes($command)
$encodedCommand = [Convert]::ToBase64String($bytes)
powershell.exe -encodedCommand $encodedCommand

您可以使用一个命令,否则-EncodedCommand只需提供一个Base64编码的字符串就可以进行笨拙的转义.