Tomcat/Spring集成返回404

Question

我在Spring 3.1 MVC应用程序上遇到与HTTP Status 404类似的问题

但我没有像海报那样犯同样的错误,但我仍然得到404.

web.xml文件:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee     http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">

<display-name>Test</display-name>

<welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
</welcome-file-list>

<servlet>
<servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>

我能够加载index.jsp但不能加载实际的控制器.

dispatcher-servlet.xml文件:

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context" 
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd">

<!-- enable Spring’s component scanning -->
<context:component-scan base-package="com.test" />

<!-- process the @RequestMapping annotations at the class level -->
<bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping" />

<!-- process the @RequestMapping annotations at the method level -->
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />

<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>

调节器

package com.test.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.ui.Model;

@Controller
public class BenchController {

@RequestMapping(value = "/bench", method = RequestMethod.GET)
@ResponseBody
public String welcome(Model model) {
  return "yo";
}

}

我可以转到localhost:8080/Test/index.jsp但localhost:8080/Test/bench返回404.

我正在使用eclipse,如果这有帮助的话.

编辑1:

这是logging.properties.除了日志外,我找不到任何日志.

handlers = 1catalina.org.apache.juli.FileHandler, 2localhost.org.apache.juli.FileHandler, java.util.logging.ConsoleHandler

.handlers = 1catalina.org.apache.juli.FileHandler, java.util.logging.ConsoleHandler

############################################################
# Handler specific properties.
# Describes specific configuration info for Handlers.
############################################################

1catalina.org.apache.juli.FileHandler.level = FINE
1catalina.org.apache.juli.FileHandler.directory = ${catalina.base}/logs
1catalina.org.apache.juli.FileHandler.prefix = catalina.

2localhost.org.apache.juli.FileHandler.level = FINE
2localhost.org.apache.juli.FileHandler.directory = ${catalina.base}/logs
2localhost.org.apache.juli.FileHandler.prefix = localhost.

java.util.logging.ConsoleHandler.level = FINE
java.util.logging.ConsoleHandler.formatter = java.util.logging.SimpleFormatter

############################################################
# Facility specific properties.
# Provides extra control for each logger.
############################################################

org.apache.catalina.core.ContainerBase.[Catalina].[localhost].level = INFO
org.apache.catalina.core.ContainerBase.[Catalina].[localhost].handlers = 2localhost.org.apache.juli.FileHandler

# For example, set the com.xyz.foo logger to only log SEVERE
# messages:
#org.apache.catalina.startup.ContextConfig.level = FINE
#org.apache.catalina.startup.HostConfig.level = FINE
#org.apache.catalina.session.ManagerBase.level = FINE
#org.apache.catalina.core.AprLifecycleListener.level=FINE

有趣的是,我不确定catalina.base变量的定义位置.

编辑2:

的pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
  <modelVersion>4.0.0</modelVersion>
  <groupId>com.test</groupId>
  <artifactId>Test</artifactId>
  <version>0.1</version>
  <packaging>war</packaging>

  <properties>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
    <spring.version>3.1.0.RELEASE</spring.version>
  </properties>
  <build>
    <plugins>
      <plugin>
        <artifactId>maven-compiler-plugin</artifactId>
        <version>2.3.2</version>
        <configuration>
      <source>1.6</source>
          <target>1.6</target>
        </configuration>
      </plugin>
      <plugin>            
        <groupId>org.apache.maven.plugins</groupId>
        <artifactId>maven-war-plugin</artifactId>
        <configuration>
          <webXml>/WebContent/WEB-INF/web.xml</webXml>
        </configuration>
      </plugin>
    </plugins>
  </build>

  <dependencies>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-core</artifactId>
      <version>${spring.version}</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-context</artifactId>
      <version>${spring.version}</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-context-support</artifactId>
      <version>${spring.version}</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-webmvc</artifactId>
      <version>${spring.version}</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-web</artifactId>
      <version>${spring.version}</version>
    </dependency>
    <dependency>
      <groupId>log4j</groupId>
      <artifactId>log4j</artifactId>
      <version>1.2.16</version>
    </dependency>
  </dependencies>
</project>

我的依赖树中没有看到log4j,即使它在我的pom文件中.

编辑3:

这是我在eclipse中创建项目的方式:

1. 新Maven项目(m2 eclipse插件)
2. 我选择了简单项目
3. 填写组/ artificat id并选择战争作为我的包装
4. 我在项目文件夹窗口中右键单击了我的项目并选择了Properties
5. 我点击Project Facets并在提示时转换它
6. 我选择了"动态Web模块"并单击确定

完成所有这些后,我开始添加调度程序,用弹簧更新pom等.

编辑4:

好吧,我终于到了某个地方.在web.xml中注释掉这一行后:

<listener>
  <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

我能够通过tomcat管理器直接部署应用程序.现在我来了

java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/dispatcher-servlet.xml]

它似乎正在尝试在/ WEB-INF文件夹下找到dispatcher-servlet.xml.查看war文件后,我找不到该文件.每次我将servlet xml放在该文件夹中时,它似乎都被删除了.我可以把它放在任何其他文件夹下,但出于某种原因,当我这样做时,它似乎仍然在更新web.xml以引用新位置后搜索/ WEB-INF下的文件.

编辑5:

这是我的web.xml上的更新

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

xmlns ="http://java.sun.com/xml/ns/javaee"xmlns:web ="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"xsi:schemaLocation = "http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"version ="2.5">

  <display-name>Test</display-name>

  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>

  <servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>WEB-INF/classes/dispatcher-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>

  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>

  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>WEB-INF/classes/applicationContext.xml</param-value>
  </context-param>

  <context-param>
    <param-name>log4jConfigLocation</param-name>
    <param-value>WEB-INF/classes/log4j.properties</param-value>
  </context-param>

  <listener>
    <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
  </listener>

</web-app>

显式添加applicationContext和dispatcher-servlet的位置后.catalina.out说:

Mapped URL path [/bench] onto handler 'benchController'
Mapped URL path [/bench.*] onto handler 'benchController'
Mapped URL path [/bench/] onto handler 'benchController'
Mapped URL path [/bench] onto handler 'benchController'
Mapped URL path [/bench/*] onto handler 'benchController'
FrameworkServlet 'dispatcher': initialization completed in 245 ms 

但是当转到localhost:8080/Test/bench时 - 它仍然返回404.当我通过tomcat管理器部署时,我无法访问index.jsp,但如果我通过eclipse部署,我可以.catalina.out没有其他输出.

日志:

127.0.0.1 - - [20/Feb/2012:14:41:13 -0800] "GET /Test/ HTTP/1.1" 200 182
127.0.0.1 - - [20/Feb/2012:14:41:19 -0800] "GET /Test/ HTTP/1.1" 200 182
127.0.0.1 - - [20/Feb/2012:14:41:24 -0800] "GET /Test/bench HTTP/1.1" 404 1012

解:

我按照下面提供的说明并在项目文件夹中,从命令行运行mvn eclipse:eclipse -Dwtpversion = 2.0,以便eclipse可以正确导入项目.我正在努力弄清楚如何通过eclipse做到这一点,以避免每次都手动执行此操作.

Answer 1

您提到过您想学习如何从头开始制作Spring MVC Web应用程序 - 以下是使用您的配置生成工作应用程序的步骤列表:

1)创建一个文件夹 a

2)在该文件夹中创建一个文件pom.xml:

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>test</groupId>
<artifactId>test</artifactId>
<name>test</name>
<packaging>war</packaging>
<version>1.0.0-SNAPSHOT</version>
<properties>
    <org.springframework.version>3.0.5.RELEASE</org.springframework.version>
</properties>
<dependencies>

    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-context</artifactId>
        <version>${org.springframework.version}</version>
    </dependency>
    <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-webmvc</artifactId>
        <version>${org.springframework.version}</version>
    </dependency>
    <dependency>
        <groupId>log4j</groupId>
        <artifactId>log4j</artifactId>
        <version>1.2.16</version>
        <scope>runtime</scope>
    </dependency>
</dependencies>
<build>
    <plugins>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-war-plugin</artifactId>
            <configuration>
                <warName>test</warName>
            </configuration>
        </plugin>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <version>2.3.2</version>
            <configuration>
                <source>1.6</source>
                <target>1.6</target>
            </configuration>
        </plugin>
    </plugins>
</build>
</project>

3)在文件夹中a创建子文件夹src/main/java/test并将文件放在YoController.java那里:

package test;

import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.*;

@Controller
public class YoController {

    @RequestMapping(value = "/bench", method = RequestMethod.GET)
    @ResponseBody
    public String welcome(Model model) {
        return "yo";
    }
}

4)创建子文件夹src/main/webapp/WEB-INF并在其中放置两个文件web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

</web-app>

并且dispatcher-servlet.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <context:component-scan base-package="test" />

</beans>

5)创建子文件夹src/main/resources并将log4j.properties文件放在那里:

log4j.rootLogger=INFO, stdout
log4j.appender.stdout=org.apache.log4j.ConsoleAppender
log4j.appender.stdout.layout=org.apache.log4j.PatternLayout

6)在文件夹a类型的命令提示符下:mvn package

7)复制target/test.war到Tomcat的webapps文件夹

8)启动Tomcat并转到URL localhost:8080/test/bench

我刚刚完成了所有步骤并且工作正常.记录显示Spring消息,告诉您是否有错误.