Doctrine DQL条件查询

2 php doctrine-orm

我正在尝试使用Doctrine的查询构建器构建动态查询.假设我也想在下面选择一个结束时间(只有输入一个).我如何有条件地将这个添加到声明中?

    $query = $this->getEntityManager()->createQueryBuilder()
        ->select('m')
        ->from($this->getEntityName(), 'm')
        ->where("m.start > '" . date('Y-m-d H:i:s', strtotime($start)) . "'")
        ->getQuery();
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Ale*_*tis 5

我会做这样的事情:

// first, create the query builder
$qb = $this->getEntityManager()->createQueryBuilder()
    ->select('m')
    ->from($this->getEntityName(), 'm')
;

// add the default condition
$conditions = array(
    $qb->expr()->gt('m.start', date('Y-m-d H:i:s', strtotime($start)));
);

// put your condition here
if (isset($end)) {
    $conditions[] = $qb->expr()->lt('m.end', date('Y-m-d H:i:s', strtotime($end)));
}

// convert the conditions to an AND clause
$conditions = call_user_func_array(array($qb, 'andX'), $conditions);

// add the WHERE clause
$qb->where($conditions);

// get the query
$query = $qb->getQuery();
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  • 这有效.谢谢!然而,它应该是:$条件= call_user_func_array(阵列($ QB-> EXPR(), '和X'),$条件); (3认同)