无法将符号转换为整数

Question

我正在尝试在Rails中实现一个简单的登录系统,但是当我尝试显示登录用户的用户名时,我收到此错误:

can't convert Symbol into Integer
Extracted source (around line #60):

57:       </ul>
58:       <% if session[:logged_in] %>
59:         <% user = session[:user] %>
60:         <p class="pull-right">Howdy, <strong><%= user[:username] %></strong>!</p>
61:       <% end %>
62:     </div>
63:   </div>

我的型号代码在这里:

require 'digest'

class User < ActiveRecord::Base

before_save {|user| user.password = Digest::SHA1.hexdigest(user.password)}
attr_accessible :username, :password, :email
validates_length_of :username, :password, :minimum => 7
validates_presence_of :username,:password,:email, :on => :create
validates_format_of :email, :with => /^([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})$/i

end

这就是我设置session [:user]的方式:

def create
    if User.find(:all, :conditions => {:username => params[:username], :password => Digest::SHA1.hexdigest(params[:username])})
        user = User.find(:all, :conditions => {:username => params[:username], :password => Digest::SHA1.hexdigest(params[:password])})
        session[:user] = user
        session[:logged_in] = true
        redirect_to(:root, :notice => "Thanks for logging in!")
    else
        redirect_to(:new, :notice => "You supplied an invalid username/password combination.")
    end
end

Answer 1

可能session[:user]不像你期望的那样是哈希,而是一个数组.因此,使用除整数之外的任何内容来订阅它是无效的.

如何解决这个问题？更改实际设置会话变量的代码(如session[:user] = XYZ).

编辑: User.find(:all, ...)返回一个数组,所以我假设你正在分配一个数组session[:user].您应该只分配找到的第一个用户(事实上,应该只有一个符合条件).更好的是,您应该只在会话中存储用户名,并在需要时从数据库中获取它:

def create
  user = User.where(:username => params[:username], :password => Digest::SHA1.hexdigest(params[:username])).first
  if user
    session[:user_id] = user.id
  else
    redirect_to(:new, :notice => "You supplied an invalid username/password combination.")
  end
end

然后在与您的视图关联的操作中:

def ...
  @user = User.find(session[:user_id])
  unless @user
    # redirect to error page, user was deleted in the meantime
  end
end

然后在视图中:

<%= @user.username %>